我有一个字符串如下:
{a{b,c}d}
如果我给 1,则字符串必须显示为:
{a d}
内大括号内的内容应与大括号一起删除。
有人可以帮我吗?
要提取 {} 的内部分组,请使用以下正则表达式:
string extract = Regex.Replace(source, "\{\w(\{\w,\w\})\w\}", "$1");
实际上,如果您想删除逗号....
string extract = Regex.Replace(source, "\{\w\{(\w),(\w)\}\w\}", "{$1 $2}");
要在没有内部分组的情况下提取外部:
string extract = Regex.Replace(source, "(\{\w)\{\w,\w\}(\w\})", "$1 $2");
如果在您的示例中 a、b、c、d 不是字面上的单个字符,即字母组甚至空格等,请将\w替换为\w+甚至.*
根据您对嵌套的评论....
string extract = Regex.Replace(source, "(\{\w)\{.*\}(\w\})\w*", "$1 $2");
你可以用手来做......几年前我在一个例子中写了一些东西......必须寻找它......:
string def = "1+2*(3/(4+5))*2";
int pcnt = 0, start = -1, end = -1;
bool subEx = false;
if(def.Contains("(") || def.Contains(")"))
for(int i = 0; i < def.Length; i++) {
if(def[i] == '(') {
pcnt++;
if(!subEx)
start = i;
} else if(def[i] == ')')
pcnt--;
if(pcnt < 0)
throw new Exception("negative paranthesis count...");
if(pcnt != 0)
subEx = true;
if(subEx && pcnt == 0 && end == -1)
end = i;
}
if(pcnt != 0) {
throw new Exception("paranthesis doesn't match...");
}
if(subEx) {
string firstPart = def.Substring(0, start);
string innerPart = def.Substring(start + 1, end - (start + 1));
string secondPart = def.Substring(end + 1);
Console.WriteLine(firstPart);
Console.WriteLine(innerPart);
Console.WriteLine(secondPart);
}
写道:
1+2*
3/(4+5)
*2
命名空间分隔符 { 类程序 { 静态无效 Main(string[] args) { string src = "a{b{c{d,e}f}g}h"; int发生计数= 0;foreach (char ch in src) { if(ch == '{') {occurrenceCount++; } } Console.WriteLine("输入要删除块的编号:"); 整数给定值 = 0; CheckValid(out givenValue);
int removeCount = occurenceCount + 1 - givenValue;
occurenceCount = 0;
int startPos = 0;
for (int i = 0; i < src.Length; i++)
{
if (src[i] == '{')
{
occurenceCount++;
}
if(occurenceCount == removeCount)
{
startPos = i;
break;
//i value { of to be removed block
}
}
int endPos = src.IndexOf('}', startPos);
src = src.Remove(startPos,endPos);
//index of }
Console.WriteLine("after reved vale:" + src);
Console.ReadKey();
}
public static void CheckValid(out int givenValue)
{
if (!int.TryParse(Console.ReadLine(), out givenValue))
{
Console.WriteLine("Enter a valid no. to remove block: ");
CheckValid(out givenValue);
}
}
}
}