5

这段代码有什么问题?
我的项目中有一个原始文件(mp4 视频文件),
当我这样做时,然后我从 SD 卡文件中检索文件不相同,因此无法加载视频:(
你有另一种方法来自动将原始文件复制到sdcard ?
谢谢

String FICHIER_BLOW = "blowvid4.mp4";
File f=new File(Environment.getExternalStorageDirectory(), FICHIER_BLOW);
try {
    if (f.createNewFile()){
    FileWriter ecrivain = new FileWriter(f);
    BufferedWriter bufEcrivain = new BufferedWriter(ecrivain);
    BufferedInputStream VideoReader = new BufferedInputStream(getResources().openRawResource(R.raw.blow));
    while( VideoReader.available() > 0 ){
        bufEcrivain.write(VideoReader.read());
    }
    bufEcrivain.close();

    VideoView videoView = (VideoView) findViewById(R.id.VideoView);
    MediaController mediaController = new MediaController(this);
    mediaController.setAnchorView(videoView);
    video =Uri.fromFile(f);
    videoView.setMediaController(mediaController);
    videoView.setVideoURI(video);
    videoView.start();
    }
} catch (IOException e) {
    // TODO Auto-generated catch block
    e.printStackTrace();
}
4

3 回答 3

9

如果使用InputStream 读取,则使用OutputStream 写入,即BufferedOutputStream 包装的FileOutputStream。此外,您的代码效率很低,因为它一次只复制一个字节。我建议创建一个字节数组缓冲区并使用这些相关的读/写方法:

int BufferedInputStream.read(byte[] buffer, int offset, int length)
void BufferedOutputStream.write(byte[] buffer, int offset, int length)
于 2010-07-30T01:03:18.120 回答
7

有效,谢谢

BufferedOutputStream bufEcrivain = new BufferedOutputStream((new FileOutputStream(f)));
BufferedInputStream VideoReader = new BufferedInputStream(getResources().openRawResource(R.raw.blow));
byte[] buff = new byte[32 * 1024];
int len;
while( (len = VideoReader.read(buff)) > 0 ){
    bufEcrivain.write(buff,0,len);
}
bufEcrivain.flush();
bufEcrivain.close();
于 2010-07-30T08:50:58.413 回答
2

我认为您应该在关闭流之前刷新

bufEcrivain.flush();
bufEcrivain.close();
于 2010-07-30T00:57:04.807 回答