这是Python中地理空间分析的后续问题
这个问题类似于https://gis.stackexchange.com/questions/84114/shapely-unable-to-tell-if-polygon-contains-point但反转纬度似乎已经解决了这个问题，但它不是帮我。
Uber 数据以 lat/long 形式给出，非常直接，反向查找在 geopandas 中使用时给出地址
然而，问题是在 shapefile 中查找那些纬度/经度。Uber 数据如下所示：
Trip ID DateTime Stamp Lat Long
00001 2007-01-07T10:56:46+00:00 37.786117 -122.440119
00001 2007-01-07T10:56:50+00:00 37.786564 -122.440209
00001 2007-01-07T10:56:54+00:00 37.786905 -122.440270
00001 2007-01-07T10:56:58+00:00 37.786956 -122.440279
00002 2007-01-06T06:22:35+00:00 37.800224 -122.433520
00002 2007-01-06T06:22:39+00:00 37.800155 -122.434101
00002 2007-01-06T06:22:43+00:00 37.800160 -122.434430
00002 2007-01-06T06:22:47+00:00 37.800378 -122.434527
00002 2007-01-06T06:22:51+00:00 37.800738 -122.434598
00002 2007-01-06T06:22:55+00:00 37.800938 -122.434650
00002 2007-01-06T06:22:59+00:00 37.801024 -122.434889
00002 2007-01-06T06:23:03+00:00 37.800955 -122.435392
00002 2007-01-06T06:23:07+00:00 37.800886 -122.435959
00002 2007-01-06T06:23:11+00:00 37.800811 -122.436275
形状文件多边形边界看起来像
(5979385.645656899, 2110931.7279282957, 5988491.7629433125, 2116394.4427246302)
(5996757.772329897, 2104615.921334222, 6002126.622484565, 2111141.524096638)
(5994970.50687556, 2086244.426253125, 6004106.84030889, 2096245.441356048)
(6005060.663860559, 2117913.4127838016, 6010794.38500464, 2123410.4359104633)
(5999414.325087652, 2098231.5748509616, 6005330.746325642, 2103724.0536953807)
(5990180.636205971, 2101104.2121503055, 5997586.527562141, 2107405.9502029717)
(6005605.349122897, 2109599.6380728036, 6010954.164540723, 2115863.756778136)
(5997399.803198054, 2095859.3430468887, 6002045.244038388, 2100357.5978298783)
(6018974.499877974, 2121660.499777794, 6024740.999827892, 2131294.0001958013)
(5980891.2469763905, 2086337.3158311248, 5992333.58203131, 2097376.2589762956)
(5979838.815354228, 2109536.4948263764, 5990061.512428477, 2115435.3563882113)
(5996370.188459396, 2086085.1349050552, 6006040.649761483, 2089160.6310506314)
(6000325.210404977, 2087887.1444243789, 6011873.615785807, 2095773.4459089637)
(5980631.069675222, 2095815.8703648, 5992293.742215976, 2101164.5775151253)
(6010609.867329061, 2112785.889902383, 6015766.567317471, 2119365.8508238047)
(5991138.3905240595, 2086268.6489737183, 5998688.01650089, 2094657.981276378)
(6004790.221816152, 2100493.380038634, 6011576.786655068, 2109303.3404370546)
(5991505.183097556, 2091674.2884248793, 6000205.414384723, 2102574.580600634)
所以 polygon/polygon.contains(point) 中的点不起作用。查看数据，与 shapely 文件相比，lat long 非常小，我不确定是否必须将一个单位转换为另一个单位，看起来完全不同的公制:) 下面是代码：
import fiona
import shapely
from shapely.geometry import Point
import geopy
from geopy.geocoders import Nominatim
from shapely.geometry import shape
fc = fiona.open('/home/user/geo/sfo_shapefile/planning_neighborhoods.shp')
print fc.schema
pol = fc.next()
for f in fc:
print shape(f['geometry']).bounds
geom = shape(pol['geometry'])
print "Bigger poly shape" ,shape(pol['geometry']).bounds
geolocator = Nominatim()
for cords in open('/home/user/geo/uber/trips.tsv'):
latlong = cords.split('\t')
p = Point(float(latlong[3]),float(latlong[2]))
p = Point(float(37.783383),float(-122.439594))
if geom.contains(p):
print geolocator.reverse(p).address
Uber 数据和 SFO shapefile 的链接在这里http://hortonworks.com/blog/magellan-geospatial-analytics-in-spark/#comment-606532