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我最近遇到了 QSignalMapper 的问题。我无法让信号映射 (QObject*) 触发

我目前有一个keyboard.qml从 c++ 类中分配和删除的 qml 对象keyboardManager.cpp。在keyboard.qml我有以下信号：

signal keyboardOpening
signal keyboardOpened
signal keyboardClosing
signal keyboardClosed

这个功能：

function close() {
    popDelay.stop();
    closing = true;
    keyboardClosing();
    state = "OFFSCREEN";
}

信号

signal keyboardClosed

当所有与状态更改相关的动画完成时触发

在 C++ 中，我有一个方法和一个插槽

//method
void KeyboardManager::beginRemoveKeyboard(TouchTextField *target);
//slot
void KeyboardManager::endRemoveKeyboard(QObject *target);

在 beginRemoveKeyboard 我尝试将 keyboardClosed 连接到 endRemoveKeyboard 以便我可以释放我的内存并正确注销所有指针，所以我做了这个测试：

在 QML 中：

onKeyboardClosed: console.debug("closed");

在 C++ 中：

void KeyboardManager::test() { qDebug() << "test"; }
void KeyboardManager::beginRemoveKeyboard(TouchTextField *target)
{
    NewKeyboard *currentKeyboard = m_keyboards.value(target);

    QSignalMapper* signalMapper = new QSignalMapper(this);

    QObject::connect(currentKeyboard, SIGNAL(keyboardClosed()), signalMapper, SLOT(map()));
    QObject::connect(currentKeyboard, SIGNAL(keyboardClosed()), this, SLOT(test()));
    signalMapper->setMapping(this, (QObject*)target);

    QObject::connect(signalMapper, SIGNAL(mapped(QObject*)), this, SLOT(endRemoveKeyboard(QObject*)));
    QMetaObject::invokeMethod(currentKeyboard, "close");
}
void KeyboardManager::endRemoveKeyboard(QObject *target)
{
    qDebug() << "deletion started";
    TouchTextField* actualTarget = qobject_cast<TouchTextField*>(target);
    NewKeyboard *currentKeyboard = m_keyboards.value(actualTarget);
    actualTarget->setKeyboard(NULL);
    m_keyboards.remove(actualTarget);
    delete currentKeyboard;
    if (sender())
        delete sender(); //QSignalMapper
}

但是，当我调用 KeyboardManager::beginRemoveKeyboard 并得到：

[DEBUG]closed (qrc:///main.qml:24, )
[DEBUG] test (tmp/debug/moc/../../../include/keyboard/KeyboardManager.h:31, void KeyboardManager::test())

就这样。没有“删除开始”，这意味着KeyboardClosed()被触发，test()被调用但endRemoveKeyboard(QObject*)不是。为什么以及如何实现我想要的？

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