谁能帮我查询mysql。我正在尝试使用插入选择语句插入多行。
if ($insert_stmt = $mysqli->prepare("INSERT INTO order_processing_info (order_id, cart_item_id, item_id, price, quantity) VALUES (?, (SELECT s.cart_item_id, i.item_id, i.price, s.quantity FROM inventory_info AS i, cart_info AS s WHERE i.item_id=s.item_id AND s.user_id = ?))")) {
$insert_stmt->bind_param('ss', $order_id, $user_id);
我认为问题是因为我希望这里所有插入的 order_id 都相同，尽管我不确定。
以前我试图在选择语句块中运行它失败。
if ($select_stmt = $mysqli->prepare("SELECT i.item_id, i.price, s.quantity, s.cart_item_id FROM inventory_info AS i, shopping_cart_info AS s WHERE i.item_id=s.item_id AND s.user_id = ?")) {
$select_stmt->bind_param("s", $user_id);
$select_stmt->execute();
$select_stmt->bind_result($item_id, $price, $quantity, $cart_item_id);
while ($select_stmt->fetch()) {
if ($insert_stmt = $mysqli->prepare("INSERT INTO order_processing_info (order_id, cart_item_id, item_id, price, quantity) VALUES (?, ?, ?, ?, ?)")) {
$insert_stmt->bind_param('sssss', $order_id, $cart_item_id, $item_id, $price, $quantity);
// Execute the prepared query.
if (!$insert_stmt->execute()) {
header('Location: ../error.php?err=INSERT failure: INSERT');
exit();
}
}
}
$select_stmt->close();
}
我在stackoverflow上查了很多，但我想我对数据库查询不是那么精通，所以如果有人能帮我解决这个问题，我将不胜感激。