28

是否可以检测笔记本电脑的盖子何时打开或关闭？从我读过的内容来看，这是不可能的，但是 SO 帮助我解决了以前的不可能。

我发现唯一可能朝着正确方向的事情是关于报告电源按钮所需的 IOCTL 的 MSDN 博客文章。是否可以在操作系统调用它们时“嗅探”它们？

我正在使用 VB.NET，但会接受任何语言的建议。感谢您的时间和建议。

编辑：我的软件将（最终）覆盖关闭盖子时发生的操作（基于用户偏好），因此不能选择在关闭盖子时侦听挂起和通常发生的其他操作。

4

5 回答 5

17

WPF 应用程序的完整工作 C# 代码，显示如何侦听盖子打开/关闭事件：

using System;
using System.Diagnostics;
using System.Runtime.InteropServices;
using System.Windows;
using System.Windows.Interop;

namespace WpfApplication1
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        [DllImport(@"User32", SetLastError = true, EntryPoint = "RegisterPowerSettingNotification",
            CallingConvention = CallingConvention.StdCall)]

        private static extern IntPtr RegisterPowerSettingNotification(IntPtr hRecipient, ref Guid PowerSettingGuid,
            Int32 Flags);

        internal struct POWERBROADCAST_SETTING
        {
            public Guid PowerSetting;
            public uint DataLength;
            public byte Data;
        }

        Guid GUID_LIDSWITCH_STATE_CHANGE = new Guid(0xBA3E0F4D, 0xB817, 0x4094, 0xA2, 0xD1, 0xD5, 0x63, 0x79, 0xE6, 0xA0, 0xF3);
        const int DEVICE_NOTIFY_WINDOW_HANDLE = 0x00000000;
        const int WM_POWERBROADCAST = 0x0218;
        const int PBT_POWERSETTINGCHANGE = 0x8013;

        private bool? _previousLidState = null;

        public MainWindow()
        {
            InitializeComponent();
            this.SourceInitialized += MainWindow_SourceInitialized;
        }

        void MainWindow_SourceInitialized(object sender, EventArgs e)
        {
            RegisterForPowerNotifications();
            IntPtr hwnd = new WindowInteropHelper(this).Handle;
            HwndSource.FromHwnd(hwnd).AddHook(new HwndSourceHook(WndProc));
        }

        private void RegisterForPowerNotifications()
        {
            IntPtr handle = new WindowInteropHelper(Application.Current.Windows[0]).Handle;
            IntPtr hLIDSWITCHSTATECHANGE = RegisterPowerSettingNotification(handle,
                 ref GUID_LIDSWITCH_STATE_CHANGE,
                 DEVICE_NOTIFY_WINDOW_HANDLE);
        }

        IntPtr WndProc(IntPtr hwnd, int msg, IntPtr wParam, IntPtr lParam, ref bool handled)
        {
            switch (msg)
            {
                case WM_POWERBROADCAST:
                    OnPowerBroadcast(wParam, lParam);
                    break;
                default:
                    break;
            }
            return IntPtr.Zero;
        }

        private void OnPowerBroadcast(IntPtr wParam, IntPtr lParam)
        {
            if ((int)wParam == PBT_POWERSETTINGCHANGE)
            {
                POWERBROADCAST_SETTING ps = (POWERBROADCAST_SETTING)Marshal.PtrToStructure(lParam, typeof(POWERBROADCAST_SETTING));
                IntPtr pData = (IntPtr)((int)lParam + Marshal.SizeOf(ps));
                Int32 iData = (Int32)Marshal.PtrToStructure(pData, typeof(Int32));
                if (ps.PowerSetting == GUID_LIDSWITCH_STATE_CHANGE)
                {
                    bool isLidOpen = ps.Data != 0;

                    if (!isLidOpen == _previousLidState)
                    {
                        LidStatusChanged(isLidOpen);
                    }

                    _previousLidState = isLidOpen;
                }
            }
        }

        private void LidStatusChanged(bool isLidOpen)
        {
            if (isLidOpen)
            {
                //Do some action on lid open event
                Debug.WriteLine("{0}: Lid opened!", DateTime.Now);
            }
            else
            {
                //Do some action on lid close event
                Debug.WriteLine("{0}: Lid closed!", DateTime.Now);
            }
        }
    }
}
于 2014-04-27T18:29:12.583 回答
8

使用 WM_POWERBROADCAST。这是一个可以帮助您的链接：盖子关闭操作更改通知

于 2010-07-28T17:53:27.223 回答
5

请记住，大多数笔记本电脑，当盖子关闭时，它会按下一个按钮。这个按钮通常只是一个睡眠按钮。WMI 类公开 ACPI，您最好使用 PowerManagement 类。不幸的是，当操作系统设置为“什么都不做”时，该类不会引发事件。解决这个问题的唯一方法是使用 DDK（驱动程序开发工具包）创建一个过滤器来拦截 IOCTL_GET_SYS_BUTTON_EVENT 事件。这里有两个链接可以帮助您入门：

http://blogs.msdn.com/b/doronh/archive/2006/09/08/746834.aspx

和

http://support.microsoft.com/kb/302092

于 2010-07-28T18:00:59.223 回答
1

这是一个解决方案；

https://www.codeproject.com/Tips/480049/Shut-Down-Restart-Log-off-or-Lock-your-computer-in

我做到了；

using System;
using System.Diagnostics;
using System.Runtime.InteropServices;
using System.Windows;
using System.Windows.Interop;

namespace WpfApplication1
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        [DllImport(@"User32", SetLastError = true, EntryPoint = "RegisterPowerSettingNotification",
            CallingConvention = CallingConvention.StdCall)]

        private static extern IntPtr RegisterPowerSettingNotification(IntPtr hRecipient, ref Guid PowerSettingGuid,
            Int32 Flags);

        internal struct POWERBROADCAST_SETTING
        {
            public Guid PowerSetting;
            public uint DataLength;
            public byte Data;
        }

        Guid GUID_LIDSWITCH_STATE_CHANGE = new Guid(0xBA3E0F4D, 0xB817, 0x4094, 0xA2, 0xD1, 0xD5, 0x63, 0x79, 0xE6, 0xA0, 0xF3);
        const int DEVICE_NOTIFY_WINDOW_HANDLE = 0x00000000;
        const int WM_POWERBROADCAST = 0x0218;
        const int PBT_POWERSETTINGCHANGE = 0x8013;

        private bool? _previousLidState = null;

        public MainWindow()
        {
            InitializeComponent();
            this.SourceInitialized += MainWindow_SourceInitialized;
        }

        void MainWindow_SourceInitialized(object sender, EventArgs e)
        {
            RegisterForPowerNotifications();
            IntPtr hwnd = new WindowInteropHelper(this).Handle;
            HwndSource.FromHwnd(hwnd).AddHook(new HwndSourceHook(WndProc));
        }

        private void RegisterForPowerNotifications()
        {
            IntPtr handle = new WindowInteropHelper(Application.Current.Windows[0]).Handle;
            IntPtr hLIDSWITCHSTATECHANGE = RegisterPowerSettingNotification(handle,
                 ref GUID_LIDSWITCH_STATE_CHANGE,
                 DEVICE_NOTIFY_WINDOW_HANDLE);
        }

        IntPtr WndProc(IntPtr hwnd, int msg, IntPtr wParam, IntPtr lParam, ref bool handled)
        {
            switch (msg)
            {
                case WM_POWERBROADCAST:
                    OnPowerBroadcast(wParam, lParam);
                    break;
                default:
                    break;
            }
            return IntPtr.Zero;
        }

        private void OnPowerBroadcast(IntPtr wParam, IntPtr lParam)
        {
            if ((int)wParam == PBT_POWERSETTINGCHANGE)
            {
                POWERBROADCAST_SETTING ps = (POWERBROADCAST_SETTING)Marshal.PtrToStructure(lParam, typeof(POWERBROADCAST_SETTING));
                IntPtr pData = (IntPtr)((int)lParam + Marshal.SizeOf(ps));
                Int32 iData = (Int32)Marshal.PtrToStructure(pData, typeof(Int32));
                if (ps.PowerSetting == GUID_LIDSWITCH_STATE_CHANGE)
                {
                    bool isLidOpen = ps.Data != 0;

                    if (!isLidOpen == _previousLidState)
                    {
                        LidStatusChanged(isLidOpen);
                    }

                    _previousLidState = isLidOpen;
                }
            }
        }

        private void LidStatusChanged(bool isLidOpen)
        {
            if (isLidOpen)
            {
                //Do some action on lid open event
                Debug.WriteLine("{0}: Lid opened!", DateTime.Now);
            }
            else
            {
                //Do some action on lid close event
                Debug.WriteLine("{0}: Lid closed!", DateTime.Now);
            }
        }
    }
}

合上盖子的时候就是锁屏。

于 2019-08-08T15:57:51.123 回答
0

电源管理

处理节能事件 到目前为止，重点是在应用程序运行时节省电池寿命。您还应该考虑一个额外的考虑：当计算机暂停操作时，您的应用程序的行为方式。这里有两个关键场景需要考虑：

  • 当计算机空闲一段时间后，活动电源方案可能会指定硬件进入待机或休眠模式。
  • 当用户采取使计算机进入暂停操作的操作时，例如合上笔记本电脑的盖子或按下电源按钮。

我希望它能给你一些方向:)

于 2010-07-28T17:45:45.513 回答