我想将加速数组转换为 repa 数组,然后使用writeImageToBMP
from repa-io 将数组写入 BMP 文件。忽略加速 io 中存在这样一个功能的事实,我只是将其用作问题的示例。拿:
{-# LANGUAGE ScopedTypeVariables #-}
import qualified Data.Array.Accelerate.Interpreter as A (run)
import Data.Array.Accelerate
import qualified Data.Array.Accelerate as A
import qualified Data.Array.Accelerate.IO as A
import qualified Data.Array.Repa as Repa
import qualified Data.Array.Repa.IO.BMP as Repa
import GHC.Word
main :: IO ()
main = do
let accelArr = A.fromList
(Z :. (2::Int) :. (1::Int))
([(1,2,3),(4,5,6)] :: [(Word8,Word8,Word8)])
computation :: A.Acc (A.Array A.DIM2 (Word8,Word8,Word8))
computation = A.map
(\triple ->
let (r',g',b') = unlift triple :: (Exp Word8,Exp Word8,Exp Word8)
in lift (constant 0,g',b')) (use accelArr)
repaArr :: Repa.Array A.A Repa.DIM2 (Word8,Word8,Word8)
repaArr = A.toRepa (A.run computation)
Repa.writeImageToBMP "out_repa.bmp" repaArr
需要包加速、加速 io、repa 和 repa-io 来编译此代码。
这不会编译,因为writeImageToBmp
repa-io 中的类型是:
writeImageToBMP
:: FilePath
-> Repa.Array Repa.U Repa.DIM2 (Word8, Word8, Word8)
-> IO ()
whereU
表示 repa 中的清单数组。GHC 错误是:
Couldn't match type ‘A.A’ with ‘Repa.U’
Expected type: Repa.Array Repa.U Repa.DIM2 (Word8, Word8, Word8)
Actual type: Repa.Array A.A Repa.DIM2 (Word8, Word8, Word8)
In the second argument of ‘Repa.writeImageToBMP’, namely ‘repaArr’
In a stmt of a 'do' block:
Repa.writeImageToBMP "out_repa.bmp" repaArr
的类型repaArr
是:
Repa.Array A.A Repa.DIM2 (Word8,Word8,Word8)
这就是为什么 GHC 抱怨它是writeImageToBMP
.
问题:如何将加速数组表示转换A
为 repa 清单数组表示U
,以便我可以调用writeImageToBMP
它?