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我正在使用 8.2 版 Postresql

几天来一直在尝试这样做，但我一直在碰壁。如何显示以下内容：

源表 || 源列 || 目标视图 || 目标列

Stg_table1|| 客户ID || 大众客户 || Customer_details_id

我遇到的最大问题是我无法将视图中的别名链接回 Source_column。这是因为 Source_table 中列的 Ordinal 位置与 Target_view 中的列不同。

我尝试过使用这些脚本，但没有成功（这会将列重新连接到使用信息模式和序数位置）

    select distinct 
a.attname AS SOURCE
, a.attname::information_schema.sql_identifier AS column_name
--,  format_type(a.atttypid, NULL)  AS Source_Type
, d.refobjid::regclass AS Source_table 
, r.ev_class::regclass AS Target_View
--, pt.Typname AS TYPE, a.*
--, c.Column_name AS Target
--, c.Data_type
from pg_attribute as a
join pg_depend as d on d.refobjid = a.attrelid and d.refobjsubid = a.attnum
join pg_rewrite as r on d.objid = r.oid
--join information_schema.columns c ON a.attnum = c.ordinal_position --and r.ev_class::regclass = c.table_schema||'.'||c.table_name
--join pg_type as pt on a.atttypid = pt.oid
JOIN pg_class 
ON pg_class.oid = a.attrelid 
   AND a.attnum > 0
where
r.ev_class = 'abc.vw_customer'::regclass
and c.table_schema||'.'||c.table_name = 'vw_customer';

我也试过这样：

SELECT distinct dependent.relname, pg_attribute.attname
, pg_attrdef.*
--, pg_attribute.attname::information_schema.sql_identifier AS column_name
--, pg_depend.objid, pg_attribute.*
FROM pg_depend 
JOIN pg_rewrite ON pg_depend.objid = pg_rewrite.oid 
JOIN pg_class as dependee ON pg_rewrite.ev_class = dependee.oid 
JOIN pg_class as dependent ON pg_depend.refobjid = dependent.oid 
JOIN pg_attribute ON pg_depend.refobjid = pg_attribute.attrelid 
    --AND pg_depend.refobjsubid = pg_attribute.attnum 
LEFT JOIN pg_attrdef ON pg_attribute.attrelid = pg_attrdef.adrelid AND pg_attribute.attnum = pg_attrdef.adnum   
WHERE dependee.relname = 'vw_customer'
--and attname in ('Customer_details_id', 'customerid')
AND pg_attribute.attnum > 0
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