这是我的示例 js 文件，我需要绘制一个和弦，但是是日食形状而不是圆形。其次，我需要知道在创建和弦图时使用矩阵是什么，我们是否能够使用简单的 json 文件（不使用矩阵）绘制和弦，如http://www.delimited.io/blog/2013/12/所述8/chord-diagrams-in-d3这里。因为在和弦的每个示例中，都会给出一些矩阵来绘制它。我是 d3 的新手，我需要学习很多东西。任何人都可以帮助真正感激它
var outerRadius = 500 / 2,
innerRadius = outerRadius - 100;
var fill = d3.scale.category20c();
var chord = d3.layout.chord()
.padding(.04)
.sortSubgroups(d3.descending)
.sortChords(d3.descending);
var arc = d3.svg.arc()
.innerRadius(innerRadius)
.outerRadius(innerRadius + 20);
var svg = d3.select('#content').append("svg")
.attr("width", outerRadius * 2)
.attr("height", outerRadius * 2)
.append("g")
.attr("transform", "translate(" + outerRadius + "," + outerRadius +
")");
d3.json("readme.json", function(error, imports) {
if (error) throw error;
var indexByName = d3.map(),
nameByIndex = d3.map(),
matrix = [],
n = 0;
// Returns the Flare package name for the given class name.
function name(name) {
return name.substring(0, name.lastIndexOf(".")).substring(6);
}
// Compute a unique index for each package name.
imports.forEach(function(d) {
if (!indexByName.has(d = name(d.name))) {
nameByIndex.set(n, d);
indexByName.set(d, n++);
}
});
// Construct a square matrix counting package imports.
imports.forEach(function(d) {
var source = indexByName.get(name(d.name)),
row = matrix[source];
if (!row) {
row = matrix[source] = [];
for (var i = -1; ++i < n;) row[i] = 0;
}
d.imports.forEach(function(d) { row[indexByName.get(name(d))]++; });
});
chord.matrix(matrix);
var g = svg.selectAll("g.group")
.data(chord.groups())
.enter().append("svg:g")
.attr("class", "group")
.on("mouseover", fade(.02))
.on("mouseout", fade(.80));
// .on("mouseover", mouseover);
//.on("mouseout", fade(1));
g.append("svg:path")
.style("stroke", "none")
.style("fill", function(d) { return fill(d.index); })
.attr("d", arc);
/* g.append("path")
.style("fill", function(d) { return fill(d.index); })
.style("stroke", function(d) { return fill(d.index); })
.attr("d", arc);*/
g.append("text")
.each(function(d) { d.angle = (d.startAngle + d.endAngle) / 2; })
.attr("dy", ".35em")
.attr("transform", function(d) {
return "rotate(" + (d.angle * 180 / Math.PI - 90) + ")"
+ "translate(" + (innerRadius + 26) + ")"
+ (d.angle > Math.PI ? "rotate(180)" : "");
})
.style("text-anchor", function(d) { return d.angle > Math.PI ? "end" : null; })
.text(function(d) { return nameByIndex.get(d.index); });
svg.selectAll(".chord")
.data(chord.chords)
.enter().append("path")
.attr("class", "chord")
.style("stroke", function(d) { return
d3.rgb(fill(d.source.index)).darker(); })
.style("fill", function(d) { return fill(d.source.index); })
//.style("opacity", 1)
.attr("d", d3.svg.chord().radius(innerRadius));
});
d3.select(self.frameElement).style("height", outerRadius * 5 + "px");