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我正在使用 restheart 为 mongodb 提供一个宁静的界面。如果通过 Chrome 发送 GET 请求，该接口已设置并运行，并提供正确的答案。但是，如果我使用 HttpURLConnection 使用以下 java 代码，我会得到一个没有内容的 201 响应。

try {
    videos = new URL("http://www.example.com:8080/myflix/videos");
    } catch (Exception et) {
        System.out.println("Videos URL is broken");
        return null;
    }
    HttpURLConnection hc = null;
    try {
        hc = (HttpURLConnection) videos.openConnection();
        String login="admin:admin"; 
        final byte[] authBytes = login.getBytes(StandardCharsets.UTF_8);
        final String encoded = Base64.getEncoder().encodeToString(authBytes);
        hc.addRequestProperty("Authorization", "Basic "+encoded);
        hc.setDoInput(true);
        hc.setDoOutput(true);
        hc.setUseCaches(false);
        hc.setRequestMethod("GET");
        hc.setRequestProperty("Accept-Encoding", "gzip, deflate, sdch");
        hc.setRequestProperty("Content-Type", "application/json");
        hc.setRequestProperty("Accept", "application/json,text/html,application/hal+json,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*");
    } catch (Exception et) {
        System.out.println("Can't prepare http URL con");
        return (null);
    }
    BufferedReader br = null;
    try {
        OutputStreamWriter writer = new OutputStreamWriter(
                hc.getOutputStream());
    } catch (Exception et) {
        System.out.println("Can't get reader to videos stream");
    }
    String inputLine;
    String sJSON = null;

    try {
        int rc = hc.getResponseCode();

使用 Java 对 resthert 接口进行身份验证的正确方法是什么？（restheart 认证的详细信息在这里Restheart 认证

4

1 回答 1

2

我做了一些更改（查找以 <== 开头的内联注释）并且它有效：

您生成身份验证请求标头的方式是正确的。当我运行你的代码时，我实际上得到了 415 不支持的媒体类型，这在注释掉 hc.setDoOutput(true) 时消失了。GET 是一个输入操作，实际上您还试图从连接中获取一个 OutStream：您实际上需要获取一个 InputStream。

    URL url;

    try {
        url = new URL("http://127.0.0.1:8080/test/huge");
    } catch (Exception et) {
        System.out.println("Videos URL is broken");
        Assert.fail(et.getMessage());
        return;
    }

    HttpURLConnection hc = null;

    try {
        hc = (HttpURLConnection) url.openConnection();

        String login = "admin:admin";
        final byte[] authBytes = login.getBytes(StandardCharsets.UTF_8);

        final String encoded = Base64.getEncoder().encodeToString(authBytes);
        hc.addRequestProperty("Authorization", "Basic " + encoded);

        System.out.println("Authorization: " + hc.getRequestProperty("Authorization"));

        hc.setDoInput(true);
        //hc.setDoOutput(true); <== removed, otherwise 415 unsupported media type
        hc.setUseCaches(false);

        hc.setRequestMethod("GET");
        hc.setRequestProperty("Accept-Encoding", "gzip, deflate, sdch");
        hc.setRequestProperty("Accept", "application/json,text/html,application/hal+json,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*");
    } catch (Exception et) {
        System.out.println("Can't prepare http URL con");
    }

    System.out.println(hc.toString());

    BufferedReader br = null;

    try {
        InputStreamReader reader = new InputStreamReader(hc.getInputStream()); // <== the request is a GET, data is in input
    } catch (Exception et) {
        System.out.println("Can't get reader to videos stream");
    }

    int rc = hc.getResponseCode();

    System.out.println("response code: " + rc);
    System.out.println("response message: " + hc.getResponseMessage());

    Assert.assertEquals(200, rc);
于 2015-10-30T11:39:58.303 回答