我正在使用 python 中的 graphics.py 设计游戏。我最初设置了所有东西,除了游戏包括点击一个可以翻转盒子颜色的盒子。例如:如果单击的框的颜色是白色,它会变成黑色。我的代码适用于将白盒变为黑色,但不会将黑盒转换为白色。我知道我在 while 循环中的 if 语句是错误的。我想知道如何在 graphics.py 中获取矩形颜色的值,以便我可以做出正确的 if 语句。
# _______________________IMPORTS_________________________
from graphics import *
import random
#________________________________________________________
win = None
m_board = []
# Description:
# Wait for the user to enter a valid move via the mouse. If the player selects a position
# outside the valid range or selects an occupied board space, the player is asked again.
# The function returns the move only when it's valid.
# Return value:
# An integer in the range 0 to 99 representing the move
def make_move():
pos = win.getMouse()
x_axis = pos.x // 50
y_axis = pos.y // 50
move = y_axis * 10 + x_axis
return move
# Description:
# Creating the initial board with random black and white boxes
# Return Value:
# None
def draw_board():
global win, m_board
color = ["white", "black"] #Creating list for the random black/white
win = GraphWin("LOGICX", 500, 600)
for y in range(0, 500, 50):
for x in range(0, 500, 50):
board_box = Rectangle(Point(x, y), Point(x + 50, y + 50))
#Setting the boxes with random black/white
board_box.setFill(color[random.randint(0, 1)])
#Adding each box to the empty list
m_board.append(board_box)
#Setting outline color to differentiate individual boxes
board_box.setOutline("grey")
board_box.draw(win)
game_running = True
while game_running:
move = make_move()
if m_board[move] == "black":
m_board[move].setFill("white")
else:
m_board[move].setFill("black")