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我有两个结构相同的表 t1 和 t2。
表 t1 比 t2 多出大约 100 多条记录。

这是 t1 的一个小样本。

| pid   | tid    | amt         | paymentdt  | paymentmnth   | startdate                 | enddate                   | updtby
| 670   | 1      | 690.00      | 2015-07-07 | 2015-07-07    | 2015-10-26 14:36:27.000   | 2015-10-26 15:42:42.000   | NULL
| 670   | 11     | 855.00      | 2015-07-07 | 2015-07-07    | 2015-10-26 14:36:27.000   | NULL                      | NULL
| 670   | 13     | 129.00      | 2015-07-29 | 2015-07-29    | 2015-10-26 14:36:27.000   | NULL                      | NULL
| 670   | 2      | 855.00      | 2015-09-01 | 2015-09-01    | 2015-10-26 15:42:42.000   | NULL                      | NULL
| Z41   | 1      | 62.35       | 2015-05-08 | 2015-05-08    | 2015-10-26 10:15:24.000   | 2015-10-26 13:08:05.000   | NULL
| Z41   | 11     | 800.00      | 2015-05-08 | 2015-05-08    | 2015-10-26 10:15:24.000   | NULL                      | NULL
| Z41   | 2      | 298.00      | 2015-06-01 | 2015-06-01    | 2015-10-26 13:08:05.000   | 2015-10-26 14:36:27.000   | NULL
| Z41   | 3      | 298.00      | 2015-07-01 | 2015-07-01    | 2015-10-26 14:36:27.000   | 2015-10-26 15:15:45.000   | NULL
| Z41   | 4      | 298.00      | 2015-08-01 | 2015-08-01    | 2015-10-26 15:15:45.000   | 2015-10-26 15:42:42.000   | NULL
| Z41   | 5      | 238.00      | 2015-09-01 | 2015-09-01    | 2015-10-26 15:42:42.000   | NULL                      | NULL

和一个小样本 t2。

| pid   | tid    | amt         | paymentdt   | paymentmnt   | startdate                 | enddate                   | updtby
| 670   | 1      | 690.00      | 2015-07-07  | 2015-07-07   | 2015-10-02 16:10:50.000   | 2015-10-02 16:35:50.000   | NULL  
| 670   | 11     | 855.00      | 2015-07-07  | 2015-07-07   | 2015-10-02 16:10:50.000   | NULL                      | NULL  
| 670   | 13     | 129.00      | 2015-07-29  | 2015-07-29   | 2015-10-02 16:10:50.000   | NULL                      | NULL  
| 670   | 2      | 855.00      | 2015-09-01  | 2015-09-01   | 2015-10-02 16:35:50.000   | NULL                      | NULL  
| Z41   | 1      | 298.00      | 2015-07-01  | 2015-07-01   | 2015-10-02 16:10:50.000   | 2015-10-02 16:23:26.000   | NULL  
| Z41   | 11     | 800.00      | 2015-05-08  | 2015-05-08   | 2015-10-02 16:10:50.000   | NULL                      | NULL  
| Z41   | 2      | 298.00      | 2015-08-01  | 2015-08-01   | 2015-10-02 16:23:26.000   | 2015-10-02 16:35:50.000   | NULL  
| Z41   | 3      | 238.00      | 2015-09-01  | 2015-09-01   | 2015-10-02 16:35:50.000   | NULL                      | NULL  
| 173   | 1      | 785.00      | 2015-07-01  | 2015-07-01   | 2015-10-02 16:16:30.000   | 2015-10-02 16:27:36.000   | NULL  
| 173   | 11     | 465.00      | 2015-05-01  | 2015-05-01   | 2015-10-02 16:16:30.000   | NULL                      | NULL

现在比较 t1 和 t2 显示 t1 中的 pid 值更多，Z41例如 tid 包括 1、2、3、4、5 和 11。但在 t2 中仅存在 1、2、3 和 11。

然而，t1 和 t2 之间的 startdate 完全不同，所以这会引起麻烦。下面是我尝试过的合并，但它基本上只是在 t2 中插入与 t1 不同的 startdate 的每一行。

MERGE INTO t2 AS tgt
USING t1 AS src
    ON tgt.pid = src.pid AND
       tgt.tid = src.tid AND
       tgt.paymentdt = src.paymentdt AND
       tgt.paymentmnt = src.paymentmnt AND
       tgt.startdate = src.startdate
WHEN MATCHED THEN
    UPDATE SET
        tgt.amt = src.amt,
        tgt.paymentdt = src.paymentdt,
        tgt.updatedby = 'MERGEDUPDATE'
WHEN NOT MATCHED THEN
    INSERT (pid, tid, amt, paymentdt, paymentmnt, startdate, enddate, updtby)
    VALUES (src.pid, src.tid, src.amt, src.paymentdt, src.paymentmnt, src.startdate, src.enddate, 'MERGEDINSERT');

通过此合并，我留下pid and tid了updtby列中显示“MERGEDINSERT”的重复项。但我想避免重复。

如何正确进行此合并以不产生重复项，但插入 t1 中存在但不存在于 t2 中的行，同时 amt, paymentdt, and paymentmnth在保持 startdate 的同时更新值？

4

2 回答 2

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如果MERGE由于获取多个记录/匹配而引发错误，则可以使用子查询中的聚合来限制源表，例如：

;WITH t1cte AS (
    select pid, tid, amt, paymentdt, paymentmnt, startdate, enddate
    from t1 a
      inner join (select pid,tid,MAX(paymentdt) as maxdt from t1 group by pid,tid) b
        on a.pid = b.pid and a.tid = b.tid and a.paymentdt = b.maxdt
        )

MERGE INTO t2 AS tgt
USING t1cte AS src
    ON tgt.pid = src.pid AND
       tgt.tid = src.tid AND
       tgt.paymentdt = src.paymentdt AND
       tgt.paymentmnt = src.paymentmnt AND
       tgt.startdate = src.startdate
WHEN MATCHED THEN
    UPDATE SET
        tgt.amt = src.amt,
        tgt.paymentdt = src.paymentdt,
        tgt.updatedby = 'MERGEDUPDATE'
WHEN NOT MATCHED THEN
    INSERT (pid, tid, amt, paymentdt, paymentmnt, startdate, enddate, updtby)
    VALUES (src.pid, src.tid, src.amt, src.paymentdt, src.paymentmnt, src.startdate, src.enddate, 'MERGEDINSERT');
于 2015-10-27T21:31:15.793 回答
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按照您描述的方式，您的合并标准应该基于pid且tid仅基于 . 尝试这个

MERGE INTO t2 AS tgt
USING t1 AS src
    ON tgt.pid = src.pid AND
       tgt.tid = src.tid 

WHEN MATCHED THEN
    UPDATE SET
        tgt.amt = src.amt,
        tgt.paymentdt = src.paymentdt,
        tgt.paymentmnth  = src.paymentmnth, 
        tgt.updatedby = 'MERGEDUPDATE'
WHEN NOT MATCHED THEN
    INSERT (pid, tid, amt, paymentdt, paymentmnt, startdate, enddate, updtby)
    VALUES (src.pid, src.tid, src.amt, src.paymentdt, src.paymentmnt, src.startdate, src.enddate, 'MERGEDINSERT');
于 2015-10-27T20:59:03.367 回答