11

基本上是这个问题的一个骗局，但有一个显着的区别——我必须使用DataContractJsonSerializer.

一个简单的

using (var stream = new MemoryStream())
{
    var serializer = new DataContractJsonSerializer(typeof(Person));
    serializer.WriteObject(stream, obj);
    ...
    return stream.ToArray();
}

生成单行 json，例如（保存在文件中时）

...{"blah":"v", "blah2":"v2"}...

有什么选项可以做到

...
{
    "blah":"v", 
    "blah2":"v2"
}
...

我可以想到后处理...有更简单的选择吗？例如，类似于DataContractSerializer 生成的格式化 xml？

using (var stream = new MemoryStream())
{
    var serializer = new DataContractJsonSerializer(typeof(T));
    // "beautify"
    using (var writer = new SomeKindOfWriter(stream))
        serializer.WriteObject(writer, obj);
    ...
    return stream.ToArray();
}

有没有办法SomeKindOfWriter在需要时美化json？

4

1 回答 1

10

https://stackoverflow.com/a/38538454/6627992

您可以使用以下标准方法来获取格式化的 Json

JsonReaderWriterFactory.CreateJsonWriter（流流，编码编码，bool ownsStream，bool indent，string indentChars）

只设置“缩进==真”

尝试这样的事情

    public readonly DataContractJsonSerializerSettings Settings = 
            new DataContractJsonSerializerSettings
            { UseSimpleDictionaryFormat = true };

    public void Keep<TValue>(TValue item, string path)
    {
        try
        {
            using (var stream = File.Open(path, FileMode.Create))
            {
                //var currentCulture = Thread.CurrentThread.CurrentCulture;
                //Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;

                try
                {
                    using (var writer = JsonReaderWriterFactory.CreateJsonWriter(
                        stream, Encoding.UTF8, true, true, "  "))
                    {
                        var serializer = new DataContractJsonSerializer(type, Settings);
                        serializer.WriteObject(writer, item);
                        writer.Flush();
                    }
                }
                catch (Exception exception)
                {
                    Debug.WriteLine(exception.ToString());
                }
                finally
                {
                    //Thread.CurrentThread.CurrentCulture = currentCulture;
                }
            }
        }
        catch (Exception exception)
        {
            Debug.WriteLine(exception.ToString());
        }
    }

注意线条

    var currentCulture = Thread.CurrentThread.CurrentCulture;
    Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;
    ....
    Thread.CurrentThread.CurrentCulture = currentCulture;

对于某些类型的 xml 序列化程序，您应该使用 InvariantCulture 以避免在具有不同区域设置的计算机上反序列化期间出现异常。例如，双精度或日期时间的无效格式有时会导致它们。

用于反序列化

    public TValue Revive<TValue>(string path, params object[] constructorArgs)
    {
        try
        {
            using (var stream = File.OpenRead(path))
            {
                //var currentCulture = Thread.CurrentThread.CurrentCulture;
                //Thread.CurrentThread.CurrentCulture = CultureInfo.InvariantCulture;

                try
                {
                    var serializer = new DataContractJsonSerializer(type, Settings);
                    var item = (TValue) serializer.ReadObject(stream);
                    if (Equals(item, null)) throw new Exception();
                    return item;
                }
                catch (Exception exception)
                {
                    Debug.WriteLine(exception.ToString());
                    return (TValue) Activator.CreateInstance(type, constructorArgs);
                }
                finally
                {
                    //Thread.CurrentThread.CurrentCulture = currentCulture;
                }
            }
        }
        catch
        {
            return (TValue) Activator.CreateInstance(typeof (TValue), constructorArgs);
        }
    }

谢谢！

于 2016-07-24T16:18:13.233 回答