1

如果我声明这样的哈希:

my %n = (a => {1 => "1a",2 => "2a"},"b" => {1 => "1b",2 => "2b"});

如何访问:n -> a -> 1 中的数据?

我试过

print "$n{a{1}}";

print "$n{a ->{ 1}}";

这两个不行

4

1 回答 1

1

参考perldsc

use warnings;
use strict;

my %n = (a => {1 => "1a",2 => "2a"},"b" => {1 => "1b",2 => "2b"});
print "$n{a}{1}\n";

__END__

1a
于 2015-10-26T18:12:29.917 回答