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我有一个消息发布服务器类，它在构造时创建一个 PUB 套接字，代码如下：

this.context = NetMQContext.Create();
this.pubSocket = this.context.CreatePublisherSocket();
var portNumber = this.installerSettings.PublisherPort;
this.pubSocket.Bind("tcp://127.0.0.1:" + portNumber);

messagePublishingServer.Publish(message)使用执行发送消息：

this.pubSocket.SendMoreFrame(string.Empty).SendFrame(message);

以下 xBehave 测试...

    [Scenario]
    public void PublishMessageScenario()
    {
        MessagePublishingServer messagePublishingServer = null;
        NetMQContext context;
        NetMQ.Sockets.SubscriberSocket subSocket = null;
        string receivedMessage = null;

        "Given a running message publishing server"._(() =>
        {
            var installerSettingsManager = A.Fake<IInstallerSettingsManager>();
            var settings = new InstallerSettings { PublisherPort = "5348" };
            A.CallTo(() => installerSettingsManager.Settings).Returns(settings);
            messagePublishingServer = new MessagePublishingServer(installerSettingsManager);
        });

        "And a subscriber connected to the publishing server"._(() =>
        {
            context = NetMQContext.Create();
            subSocket = context.CreateSubscriberSocket();
            subSocket.Options.ReceiveHighWatermark = 1000;
            subSocket.Connect("tcp://127.0.0.1:5348");
            subSocket.Subscribe(string.Empty);
        });

        "When publishing a message"._(() =>
        {
            messagePublishingServer.Publish("test message");

            // Receive the topic
            subSocket.ReceiveFrameString();

            // and the message
            receivedMessage = subSocket.ReceiveFrameString();
        });

        "Then the subscriber must have received it"._(() =>
        {
            receivedMessage.Should().NotBeNullOrEmpty();
            receivedMessage.Should().Be("test message");
        });
    }

...块在subSocket.ReceiveFrameString()我发现意外的第一个。订阅者套接字不应该在调用接收之前将发布的消息排队吗？

4

2 回答 2

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发布者就像收音机，如果您在发布者发布时没有连接和订阅，您就会错过消息。我的建议是在订阅者连接后休眠 100 毫秒（仅用于测试）。

于 2015-10-26T23:31:42.413 回答
0

从源（ReceivingSocketExtensions.cs）：

    /// Receive a single frame from socket, blocking until one arrives, and decode as a string using ...
    public static string ReceiveFrameString([NotNull] this IReceivingSocket socket)

和

    /// If no message is immediately available, return <c>false</c>.
    public static bool TryReceiveFrameString([NotNull] this IReceivingSocket socket, out string frameString)
于 2015-10-26T18:26:47.317 回答