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我有一组包装 C++ 方法调用的 lambda，我想用 LLVM 调用它们。我的尝试似乎遗漏了一些东西，即使在声明了类型并将全局映射添加到 lambda 之后，我也收到了 LLVM 错误。重现我尝试过的最小代码是：

#include "llvm/ExecutionEngine/GenericValue.h"
#include "llvm/ExecutionEngine/Interpreter.h"
#include "llvm/IR/Constants.h"
#include "llvm/IR/IRBuilder.h"
#include "llvm/Support/ManagedStatic.h"
#include "llvm/Support/TargetSelect.h"

using namespace llvm;

int main() {

  InitializeNativeTarget();

  LLVMContext Context;

  std::unique_ptr<Module> Owner = make_unique<Module>("SomeModule", Context);
  Module *M = Owner.get();

  FunctionType *lambdaFT = FunctionType::get(Type::getInt32Ty(Context), false);
  Function *lambdaFN = Function::Create(lambdaFT, Function::ExternalLinkage, "lambda", Owner.get());
  //this is what the original question had
  //auto lambdaBody = []() { return 100; };
  //this is an edit after Johannes Schaub's answer
  int32_t ( *lambdaBody)() = +[]() { return 100; };

  Function *mainF = cast<Function>(M->getOrInsertFunction("main", Type::getInt32Ty(Context), (Type *) 0));

  BasicBlock *BB = BasicBlock::Create(Context, "EntryBlock", mainF);
  IRBuilder<> builder(BB);

  CallInst *lambdaRes = builder.CreateCall(lambdaFN, std::vector<Value *>(), "lambdaRetVar");
  builder.CreateRet(lambdaRes);

  ExecutionEngine *EE = EngineBuilder(std::move(Owner)).create();
  EE->addGlobalMapping(lambdaFN, &lambdaBody);

  outs() << "We just constructed this LLVM module:\n\n" << *M;
  outs() << "\n\nRunning main: ";

  std::vector<GenericValue> noargs;
  GenericValue gv = EE->runFunction(mainF, noargs);

  outs() << "Result: " << gv.IntVal << "\n";
  llvm_shutdown();
  delete EE;
  return 0;
}

这导致输出：

We just constructed this LLVM module:

; ModuleID = 'SomeModule'

declare i32 @lambda()

define i32 @main() {
EntryBlock:
  %lambdaRetVar = call i32 @lambda()
  ret i32 %lambdaRetVar
}

Running main: 
LLVM ERROR: Tried to execute an unknown external function: lambda

我究竟做错了什么？使用 LLVM 3.7.0（标签不存在）

4

2 回答 2

1

你的 lambda body 是一个类。您必须传递其函数调用运算符的地址，您可以通过将其转换为函数指针来做到这一点：auto lambdaBody = +[]() { return 100; };并将其作为void*:传递EE->addGlobalMapping(lambdaFN, reinterpret_cast<void*>(lambdaBody));。

于 2015-10-25T11:04:40.580 回答
0

Johannes Schaub的关于 lambda 的回答有所帮助，但事实证明addGlobalMapping并没有像我想的那样。也缺少一些东西。最重要的是：

EE->InstallLazyFunctionCreator([&](const std::string &fnName) -> void * {
    if (fnName == "lambda") { return reinterpret_cast<void *>(lambdaBody); }
    return nullptr;
  });

InstallLazyFunctionCreator当函数无法解析时使用。它使用函数的名称调用，作为响应，nullptr如果未找到该函数或要执行的函数，则该函数返回。

这是完整的代码清单，还有一些附加内容（并非全部必需）：

#include "llvm/ExecutionEngine/GenericValue.h"
#include "llvm/ExecutionEngine/Interpreter.h"
#include "llvm/ExecutionEngine/RTDyldMemoryManager.h"
//must include to avoid "JIT has not been linked in" when creating the ExecutionEngine - https://llvm.org/bugs/show_bug.cgi?id=22910
#include "llvm/ExecutionEngine/MCJIT.h"
#include "llvm/IR/Constants.h"
#include "llvm/IR/IRBuilder.h"
#include "llvm/Support/ManagedStatic.h"
#include "llvm/Support/TargetSelect.h"
#include <iostream>

using namespace llvm;

int proxy() { return 1000; }

int main() {

  InitializeNativeTarget();
  llvm::InitializeNativeTargetAsmPrinter();
  llvm::InitializeNativeTargetAsmParser();

  LLVMContext Context;

  std::unique_ptr<Module> Owner = make_unique<Module>("SomeModule", Context);
  Module *M = Owner.get();

  FunctionType *lambdaFT = FunctionType::get(Type::getInt32Ty(Context), false);
  Function *lambdaFN = Function::Create(lambdaFT, Function::ExternalLinkage, "lambda", Owner.get());
  int32_t ( *lambdaBody)() = +[]() { return 9099899; };

  assert(9099899 == lambdaBody()); //make sure we can call it
  Function *mainF = cast<Function>(M->getOrInsertFunction("main", Type::getInt32Ty(Context), (Type *) 0));

  BasicBlock *BB = BasicBlock::Create(Context, "EntryBlock", mainF);
  IRBuilder<> builder(BB);

  CallInst *lambdaRes = builder.CreateCall(lambdaFN, std::vector<Value *>(), "lambdaRetVar");
  builder.CreateRet(lambdaRes);
  EngineBuilder eb(std::move(Owner));
  std::unique_ptr<RTDyldMemoryManager> MM;
  std::string Error;
  ExecutionEngine *EE = eb.setEngineKind(EngineKind::JIT)
                          .setMCJITMemoryManager(std::move(MM))
                          .setErrorStr(&Error)
                          .setOptLevel(CodeGenOpt::None)
                          .setCodeModel(CodeModel::JITDefault)
                          .setRelocationModel(Reloc::Default)
                              //.setMArch(MArch)
                          .setMCPU(sys::getHostCPUName())
                              //.setMAttrs(MAttrs)
                          .create();
  std::cout << Error << std::endl;
  EE->InstallLazyFunctionCreator([&](const std::string &fnName) -> void * {
    if (fnName == "lambda") { return reinterpret_cast<void *>(lambdaBody); }
    return nullptr;
  });
  EE->finalizeObject();
  outs() << "We just constructed this LLVM module:\n\n" << *M;
  outs() << "\n\nRunning main: ";

  std::vector<GenericValue> noargs;
  GenericValue gv = EE->runFunction(mainF, noargs);

  outs() << "Result: " << gv.IntVal << "\n";
  assert(gv.IntVal == 9099899);
  llvm_shutdown();
  delete EE;
  return 0;
}
于 2015-10-31T10:13:45.437 回答