css - 在 Less 中使用受保护的命名空间将 Mixin 转换为 Sass

Question

如何将以下用 LESS 编写的 mixin 转换为 SASS？

.box_gradient (@from, @to) when (iscolor(@from)) and (iscolor(@to)) {
  background-image: -webkit-gradient(linear, left top, left bottom, from(@from), to(@to)); /* Saf4+, Chrome */
  background-image: -webkit-linear-gradient(top, @from, @to); /* Chrome 10+, Saf5.1+, iOS 5+ */
  background-image:    -moz-linear-gradient(top, @from, @to); /* FF3.6 */
  background-image:     -ms-linear-gradient(top, @from, @to); /* IE10 */
  background-image:      -o-linear-gradient(top, @from, @to); /* Opera 11.10+ */
  background-image:         linear-gradient(to bottom, @from, @to);
}

Answer 1

这是在 SASS 中使用条件语句完成的：

.box_gradient (@from, @to) {
  @if (iscolor(@from) and iscolor(@to)) {
    background-image: -webkit-gradient(linear, left top, left bottom, from(@from),   to(@to)); /* Saf4+, Chrome */
    background-image: -webkit-linear-gradient(top, @from, @to); /* Chrome 10+,   Saf5.1+, iOS 5+ */
    background-image:    -moz-linear-gradient(top, @from, @to); /* FF3.6 */
    background-image:     -ms-linear-gradient(top, @from, @to); /* IE10 */
    background-image:      -o-linear-gradient(top, @from, @to); /* Opera 11.10+ */
    background-image:         linear-gradient(to bottom, @from, @to);
  }
}