regex - 带有反引号的 grep 正则表达式匹配所有行

Question

$ cat file
anna
amma
kklks
ksklaii

$ grep '\`' file
anna
amma
kklks
ksklaii

为什么？那场比赛如何运作？

Answer 1

这似乎是正则表达式的 GNU 扩展。反引号 ('\`') 锚匹配主题字符串的开头，这解释了为什么它匹配所有行。OS X 显然没有实现 GNU 扩展，这可以解释为什么您的示例与那里的任何行都不匹配。见http://www.regular-expressions.info/gnu.html

如果您想在 GNU 扩展生效时匹配实际的反引号，这对我有用：

grep '[`]' file

Answer 2

twm's answer provides the crucial pointer, but note that it is the sequence \`, not ` by itself that acts as the start-of-input anchor in GNU regexes.

Thus, to match a literal backtick in a regex specified as a single-quoted shell string, you don't need any escaping at all, neither with GNU grep nor with BSD/macOS grep:

$ { echo 'ab'; echo 'c`d'; } | grep '`'
c`d

When using double-quoted shell strings - which you should avoid for regexes, for reasons that will become obvious - things get more complicated, because you then must escape the ` for the shell's sake in order to pass it through as a literal to grep:

$ { echo 'ab'; echo 'c`d'; } | grep "\`"
c`d

Note that, after the shell has parsed the "..." string, grep still only sees `.

To recreate the original command with a double-quoted string with GNU grep:

$ { echo 'ab'; echo 'c`d'; } | grep "\\\`" # !! BOTH \ and ` need \-escaping
ab
c`d

Again, after the shell's string parsing, grep sees just \`, which to GNU grep is the start-of-the-input anchor, so all input lines match.

• Also note that since grep processes input line by line, \` has the same effect as ^ the start-of-a-line anchor; with multi-line input, however - such as if you used grep -z to read all lines at once - \` only matches the very start of the whole string.

To BSD/macOS grep, \` simply escapes a literal `, so it only matches input lines that contain that character.