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您好,我正在尝试使用下面的代码获得多列显示(如果可以这样调用),结果如下:替代文字 . 有人能看出为什么这些叶子是坏的吗?或者请告诉我哪个更好:链接到子类别的类别表或邻接模型列表。

 $stmt = $conn->prepare("SELECT  node.idCat_ad ,node.".$cat_name.",(COUNT(parent.".$cat_name.") - 1) AS depth 
                       FROM cat_ad AS node 
                       CROSS JOIN cat_ad AS parent 
                       WHERE node.left_node BETWEEN parent.left_node AND parent.right_node
                       GROUP BY node.idCat_ad
                       ORDER BY node.left_node"); 

$stmt->execute();
$treeArray = $stmt->fetchAll();
?>

<div class="column_in_categories">
<div class="menucategories"><ul>

<?php
$x = 0; //counter
$num_cols = 3; //3 colums
$num_rows = count($resTree); //num columns

$result = ''; 

$newArray =array_slice($resTree,1); //removing the root tree

foreach ($newArray as $currNode) { 

   if ($currNode['depth'] ==1) { //no links in root

     $result .= '<li class="header '.$classSprites.'">' . $currNode[$cat_name] . '</li>';

  } else{ //if child, we put a link

   $result .= '<li class="subcat"><a href="#">' . $currNode[$cat_name] . '</a></li>';
  }

 $x++; // incrementing da counter

 if ($x == ceil($num_rows / $num_cols)) { //if a colunm, we clause it and begin another

   $result .= '</ul></div> <div class="menucategories"><ul><li style="display:none;">&nbsp;</li>';
   $x=0; //
  }

} 
$result .="</ul></div>";
print $result;

序列化版本链接文本

4

1 回答 1

0

代替

foreach ($newArray as $currNode) { 

   if ($currNode['depth'] ==1) { //no links in root

     $result .= '<li class="header '.$classSprites.'">' . $currNode[$cat_name] . '</li>';

  } else{ //if child, we put a link

   $result .= '<li class="subcat"><a href="#">' . $currNode[$cat_name] . '</a></li>';
  }

 $x++; // incrementing da counter

 if ($x == ceil($num_rows / $num_cols)) { //if a colunm, we clause it and begin another

   $result .= '</ul></div> <div class="menucategories"><ul><li style="display:none;">&nbsp;</li>';
   $x=0; //
  }

} 

经过

foreach ($newArray as $currNode) { 

 $x++; // incrementing da counter

 if ($x >= ceil($num_rows / $num_cols) and $currNode['depth'] ==1) { //if a colunm, we clause it and begin another

   $result .= '</ul></div> <div class="menucategories"><ul><li style="display:none;">&nbsp;</li>';
   $x=0; //
  }

   if ($currNode['depth'] ==1) { //no links in root

     $result .= '<li class="header '.$classSprites.'">' . $currNode[$cat_name] . '</li>';

  } else{ //if child, we put a link

   $result .= '<li class="subcat"><a href="#">' . $currNode[$cat_name] . '</a></li>';
  }

} 

这只会在新标题开始时开始新列。

于 2010-07-24T14:28:47.093 回答