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我在我的项目中使用VichUploaderBundle
我无法获取下载链接(使用vich_file表单类型时)以考虑环境(尤其是dev)。我想做的,因为我想通过一个函数来路由下载功能。

我的配置是这样的;

vich_uploader:
    db_driver: orm
    twig:      true
    mappings:
        logo_image:
            uri_prefix:         /foo/image
            upload_destination: %kernel.root_dir%/../app/private/images
            inject_on_load:     false
            delete_on_update:   true
            delete_on_remove:   true

http://example.com/foo/image/fubar.jpg无论环境如何,这都会生成 的下载 uri 。
在开发环境中应该是http://example.com/app_dev.php/foo/image/fubar.jpg,或者在测试环境中 http://example.com/app_test.php/foo/image/fubar.jpg

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1 回答 1

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一种可能的解决方案是使用可以访问路由器类的自定义文件命名器类。在配置中设置uri_prefix/

vich_uploader:
    db_driver: orm
    twig:      true
    mappings:
        logo_image:
            uri_prefix:         /
            upload_destination: %kernel.root_dir%/../app/private/images
            inject_on_load:     false
            delete_on_update:   true
            delete_on_remove:   true
            namer: my.namer.foo

创建一个服务命​​名器类,该类返回带有所需路由的完整 url(带参数);

<?php
namespace AppBundle\Service;

use Vich\UploaderBundle\Naming\NamerInterface,
    Vich\UploaderBundle\Mapping\PropertyMapping;
use Symfony\Bundle\FrameworkBundle\Routing\Router;
class MyNamer implements NamerInterface 
{

    private $router;

    public function __construct(Router $router) 
    {
        $this->router = $router;
    }

    public function name($foo, PropertyMapping $mapping) 
    {
        $router = $this->router->getContext();
        $full_url = $router->getHost();
        $full_url .= $router->getBaseUrl().'/';
        $full_url .= 'foo/logo/'.strtolower($foo->getName());
        return $full_url;
    }

}

将其注册为服务;

services:
    my.namer.foo:
        class: AppBundle\Service\MyNamer
        arguments: ['@router']
        tags:
            - { name: namer }
于 2015-10-20T11:51:09.783 回答