c++ - 无法在 VS10 中订购weak_ptr

Question

我无法使用 VS10 让 'operator <' 为 Weak_ptr 进行编译。我是否缺少#include 或#using？

即使是文档中的代码示例也不适合我。 http://msdn.microsoft.com/en-us/library/bb982759.aspx

// temp.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"

// std_tr1__memory__operator_lt.cpp
// compile with: /EHsc
#include <memory>
#include <iostream>

int main()
{
    std::shared_ptr<int> sp0(new int(0));
    std::shared_ptr<int> sp1(new int(0));

    std::cout << "sp0 < sp0 == " << std::boolalpha
        << (sp0 < sp0) << std::endl;
    std::cout << "sp0 < sp1 == " << std::boolalpha
        << (sp0 < sp1) << std::endl;
    std::cout << "sp1 < sp0 == " << std::boolalpha
        << (sp1 < sp0) << std::endl;
    std::cout << std::endl;

    std::weak_ptr<int> wp0(sp0);
    std::weak_ptr<int> wp1(sp1);

    std::cout << "wp0 < wp0 == " << std::boolalpha
        << (wp0 < wp0) << std::endl;
    std::cout << "wp0 < wp1 == " << std::boolalpha
        << (wp0 < wp1) << std::endl;
    std::cout << "wp1 < wp0 == " << std::boolalpha
        << (wp1 < wp0) << std::endl;
}

Answer 1

事实证明，头文件中没有未注释的 'bool operator<(const weak_ptr&, const weak_ptr&) 。因此，与文档相反，这是不受支持的。