我必须创建一个采用 1-6 位二进制的代码,如果字符串不是 6,则用 0 填充最高有效位,并使用 XOR 操作比较 2 个 3 位数据包。输出很奇怪,我认为这是因为我在进行 XOR 时比较的是整数 0,而不是二进制数 0,它搞砸了。
char binary[300];
cin >> binary;
int size = strlen(binary);
//cout << "Size: " << size << endl;
int a,b,c,d,e,f;
if(size == 1){
a = 0;
b = 0;
c = 0;
d = 0;
e = 0;
f = binary[0];
cout << a^d << b^e << c^f << endl;
return 0;
}
if(size == 2){
a = 0;
b = 0;
c = 0;
d = 0;
e = binary[0];
f = binary[1];
cout << a^d << b^e << c^f << endl;
return 0;
}
if (size == 3){
a = 0;
b = 0;
c = 0;
d = binary[0];
e = binary[1];
f = binary[2];
cout << a^d << b^e << c^f << endl;
return 0;
}
if (size == 4){
a = 0;
b = 0;
c = binary[0];
d = binary[1];
e = binary[2];
f = binary[3];
cout << a^d << b^e << c^f << endl;
return 0;
}
if (size == 5){
a = 0;
b = binary[0];
c = binary[1];
d = binary[2];
e = binary[3];
f = binary[4];
cout << a^d << b^e << c^f << endl;
return 0;
}
if (size == 6){
a = binary[0];
b = binary[1];
c = binary[2];
d = binary[3];
e = binary[4];
f = binary[5];
cout << a^d << b^e << c^f << endl;
return 0;
}
return 0;