2

是否可以通过选项卡活动调用 listactivity？基本上，我正在开发一个带有 3 个选项卡的应用程序，为此我使用了 tabactivity。此外，在其中一个选项卡中我想要一个列表视图，所以我从 listactivity 派生。

现在我希望在列表视图中确定单击事件。我错过了什么吗？

public class Tabissue extends TabActivity 
{
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) 
{
    super.onCreate(savedInstanceState);

    TabHost host    =   getTabHost();

    host.addTab(host.newTabSpec("Tab1").setIndicator("Tab1").setContent(new Intent(this,Tab1.class)));
    host.addTab(host.newTabSpec("Tab2").setIndicator("Tab2").setContent(new Intent(this,Tab2.class)));
    host.setCurrentTab(1);
}
}

Tab1 类

public class Tab2 extends ListActivity
   {
  ListView list;
  @Override

public void onCreate(Bundle savedInstanceState) 
{

    super.onCreate(savedInstanceState); 
    setContentView(R.layout.tab2);    

    ArrayList<HashMap<String, String>> mylist = new ArrayList<HashMap<String, String>>();
    HashMap<String, String> map = new HashMap<String, String>();
    map.put("Test1","####");
    map.put("Test2", "India");
    map.put("Time", "India time");
    mylist.add(map);
    map = new HashMap<String, String>();
    map.put("Test1", "####");
    map.put("Test2", "US");
    map.put("Time","US time");
    mylist.add(map);
    map = new HashMap<String, String>();
    map.put("Test1", "####");
    map.put("Test2", "UK");
    map.put("Time", "UK Time");
    mylist.add(map);

    ListAdapter mSchedule = new SimpleAdapter(  this,
            mylist, 
            R.layout.row,
            new String[] 
            {
                "India", 
                "US", 
                "UK"
            }, 
            new int[] 
            {
                R.id.TRAIN_CELL, 
                R.id.FROM_CELL, 
                R.id.TO_CELL,
            }
        );
    list.setAdapter(mSchedule);    


}

}

4

1 回答 1

2

在您的 ListActivity 中设置 onItemClickListener：

getListView().setOnItemClickListener(new OnItemClickListener() {

            @Override
            public void onItemClick(AdapterView<?> av, View v, int position,
                    long id) {
                // Do your stuff here
            }
});
于 2010-07-20T17:23:33.440 回答