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我为我的 NHibernate 数据库模型定义了一个复合 ID。我也使用了外键关系中定义的列之一。如果我使用 NHibernate 插入一个对象，我会得到以下异常：

System.IndexOutOfRangeException：此 SqlParameterCollection 的索引 7 无效，Count=7。
在 System.Data.SqlClient.SqlParameterCollection.RangeCheck(Int32 index)
在 System.Data.SqlClient.SqlParameterCollection.GetParameter(Int32 index)
在 NHibernate.Type.Int32Type.Set(IDbCommand rs, Object value, Int32 index)
在 NHibernate.Type .NullableType.NullSafeSet(IDbCommand cmd, Object value, Int32 index)
at NHibernate.Type.NullableType.NullSafeSet(IDbCommand st, Object value, Int32 index, ISessionImplementor session)
at NHibernate.Type.ComponentType.NullSafeSet(IDbCommand st, Object value, Int32 开始，ISessionImplementor 会话）
在 NHibernate.Persister.Entity.AbstractEntityPersister.Dehydrate(Object id, Object[] fields, Object rowId, Boolean[] includeProperty, Boolean[][] includeColumns, Int32 table, IDbCommand statement, ISessionImplementor session, Int32 index)
在 NHibernate.Persister .Entity.AbstractEntityPersister.Insert(Object id, Object[] fields, Boolean[] notNull, Int32 j, SqlCommandInfo sql, Object obj, ISessionImplementor session)
at NHibernate.Persister.Entity.AbstractEntityPersister.Insert(Object id, Object[] fields , 对象 obj, ISessionImplementor session)
在 NHibernate.Impl.StatelessSessionImpl.Insert(String entityName, Object entity)
在 NHibernate.Impl.StatelessSessionImpl.Insert(Object entity)

是否可以将一列用于两种不同的目的（外键关系和主键）？

C# NHibernate 模型

public const string STR_ID = "Id";
public const string STR_SHARDKEY = "ShardKey";
public const string STR_OTHERMODEL = "OtherModel";

[CompositeId(-4)]
[KeyProperty(-3, Name = STR_ID, Column = STR_ID)]
[KeyProperty(-2, Name = STR_SHARDKEY , Column = STR_SHARDKEY )]
[Generator(-1, Class = "guid.comb")]
public virtual Guid? Id { get; set; }

[Column(Name = STR_SHARDKEY )]
public virtual int ShardKey{ get; set; }

[ManyToOne(0)]
[Column(1, Name = STR_OTHERMODEL )]
[Column(2, Name = STR_SHARDKEY )]
public virtual OtherModel OtherModel { get; set; }

XML 映射

<composite-id>
    <key-property name="Id" column="Id" />
    <key-property name="ShardKey" column="ShardKey" />
</composite-id>

<many-to-one name="OtherModel" >
    <column name="OtherModel" />
    <column name="ShardKey" />
</many-to-one>
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0 回答 0