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我想分别定义条形图上每个数据点的颜色，以在条形图上添加额外的信息层。我没有找到解决方案

我知道R plot 中组的不同颜色，答案表明每个数据点都不可能。我对吗？

解决它的一种方法可能是在 for 循环中逐列绘制它，但随后 x 位置被搞砸了

d = c (1,3,4);
e = c (2,3,4)
f = c (2,6,5)
data = list (d, e, f)
stripchart (data, vertical =T, pch =21, bg = 1, col=2)

可以说，我想用红色着色素数，用蓝色着色非素数。或偶数和奇数。

最通用的解决方案将采用与 input 相同维度的颜色列表，其中每个值定义绘制的相应数据点的颜色。

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3 回答 3

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当对多个组使用条形图时，使用公式界面，您可以在现有绘图中添加一个额外的条形图。但是，如果您使用抖动将无济于事。

mydata <- data.frame (x = rnorm(30), group = gl(3, 10, labels = letters[1:3]))
stripchart(x ~ group, data = mydata)
makered <- mydata$group == "b" & mydata$x < 1
stripchart(x ~ group, data = mydata[makered, ], col = "red", add = TRUE)
于 2019-04-02T06:07:51.283 回答
1

这是一个可用于解决类似问题的解决方案。简而言之，您绘制条形图，使用 gridGraphics 包将绘图转换为 grob，然后仅通过编辑 grob 来更改图形基元。

library(gridGraphics)
grid.newpage()

# Get some data
sample(x = 1:100, size = 50) -> data

# Grab plot...Now it's a grob you can modify
stripchart (data, vertical =T, pch =21, bg = 1, col=2)
grid.echo()
grid.grab() -> mygrob

# Pull out the values of the data and strip unit class
mygrob$children$`graphics-plot-1-points-1`$y -> myunits
convertUnit(myunits, "native", valueOnly = TRUE) -> myunits

# Some data to reference ours against...You can use a test for if your data is a prime, equal number, odd number, whatever..I'm just going to test if my data is in this vector and specify the color based on the results from this test.
sample(1:100, size = 10) -> sampleVec
ifelse(myunits %in% sampleVec, "red", "green") -> updatedCols

# Now sub in the new color specs for the points
mygrob$children$`graphics-plot-1-points-1`$gp$col <- updatedCols
mygrob$children$`graphics-plot-1-points-1`$gp$fill <- updatedCols

# ...And plot
grid.draw(mygrob)

在此处输入图像描述

于 2015-09-28T23:59:31.200 回答
1

然后将它们一一绘制，并使用bg=参数仍然更简单：

# generate fake data
datalist = list( rnorm(100), rnorm(100, sd = 1),rnorm(100, sd = 2) )
# generate color value for each data point  (say I want to color by each values sign +/-)
colorlist = lapply(datalist, sign)
plot(0,0,type="n",xlim=c(0.5,3.5), ylim=c(-10,10),  xaxt = 'n', xlab ="", ylab = "value",  main ="Smear")
for (i in 1:3) { stripchart(na.omit(datalist[[i]]), at = i, add = T, bg = colorlist[[i]]+2, vertical = T, pch =21, method = "jitter") }
axis(side=1,at=1:3,labels=3:1)
于 2015-10-06T09:50:23.780 回答