3

我有两个对象一个是仪表板，第二个是房间我有一个看起来像这样的 json 

  {
"hotel_id":"1",
"hotel_room":"200",
"hotel_properties":[{
        "id":"1",
        "room_type":"Single",
        "rack_rate":"2000",
        "publish_rate":"1800",
        "discount":"10",
        "availiable":"40",
        "total":"50"
      },
      {
        "id":"2",
        "room_type":"Double",
        "rack_rate":"4000",
        "publish_rate":"3600",
        "discount":"10",
        "availiable":"45",
        "total":"50"
      }
      ] 
  }

对象是

public class DashBoard {
    private int hotel_id;
    private int hotel_room;
    @JsonProperty("hotel_properties")
    private Room hotel_properties;
    }

还有另一个对象室，看起来像这样

public class Room { 
    private Long id;
    private String room_type;
    private String rack_rate;
    private String publish_rate;
    private String discount;
    private String availiable;
    private String total;
}

我隐藏了 Stackoverflow 的所有构造函数、setter 和 getter，但在我的代码中，我想使用此代码从 URL 中使用 ObjectMapper 将 Json 解析为 Object

JsonReader jsonReader = new JsonReader();
        ObjectMapper mapper = new ObjectMapper();
        try {
            JSONObject json =  jsonReader.readJsonFromUrl("http://localhost/quinchy/json/dashboard.json");
            DashBoard dsh = mapper.readValue(json.toString(), DashBoard.class); 
            System.out.println(json.toString());
        } catch (IOException | JSONException e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

但我得到这个错误

org.codehaus.jackson.map.JsonMappingException: Can not deserialize instance of Object out of START_ARRAY token

请帮我解决这个问题

4

1 回答 1

4

从JSON您发布的字符串中，看起来有一个Room对象列表。但是您使用了单个对象。

在你的DashBoard课堂上，尝试改变：

private Room hotel_properties;

至：

private List<Room> hotel_properties;
于 2015-09-26T08:43:19.337 回答