我有一个带有“消息”的二进制文件,我正在尝试使用结构将字节放入正确的变量中。在我的示例中,我使用了两种类型的消息:Tmessage 和 Amessage。
#include <iostream>
#include <fstream>
#include <stdlib.h>
#include <string>
#include <iomanip>
using namespace std;
struct Tmessage
{
unsigned short int Length;
char MessageType;
unsigned int Second;
};
struct Amessage
{
unsigned short int Length;
char MessageType;
unsigned int Timestamp;
unsigned long long int OrderReferenceNumber;
char BuySellIndicator;
unsigned int Shares;
char Stock[6];
unsigned int Price;
};
int main(int argc, char* argv[])
{
const char* filename = argv[1];
fstream file(filename, ios::in | ios::binary);
unsigned long long int pi = 0;
if(file.is_open()){ cout << filename << " OPENED" << endl; }
else { cout << "FILE NOT OPENED" << endl; }
unsigned char* memblock;
memblock = new unsigned char[128];
file.read((char *)memblock, 128);
cout << "BINARY DATA" << endl;
while (pi < 128)
{
cout << setw(2) << hex << static_cast<unsigned int>(memblock[pi]) << " ";
pi++;
if((pi%16)==0) cout << endl;
}
unsigned int poi = 0;
Tmessage *Trecord;
Trecord = (Tmessage *)memblock;
cout << "Length: " << hex << (*Trecord).Length << endl;
cout << "Message type: " << hex << (*Trecord).MessageType << endl;
cout << "Second: " << hex << (*Trecord).Second << endl;
poi = poi + 7; cout << endl;
Amessage *Arecord;
Arecord = (Amessage *)(memblock+poi);
cout << "Length: " << hex << (*Arecord).Length << endl;
cout << "Message type: " << hex << (*Arecord).MessageType << endl;
cout << "Timestamp: " << hex << (*Arecord).Timestamp << endl;
cout << "OrderReferenceNumber: " << hex << (*Arecord).OrderReferenceNumber << endl;
cout << "BuySellIndicator: " << hex << (*Arecord).BuySellIndicator << endl;
cout << "Shares: " << hex << (*Arecord).Shares << endl;
cout << "Stock: " << hex << (*Arecord).Stock << endl;
cout << "Price: " << hex << (*Arecord).Price << endl;
delete memblock;
file.close();
cout << endl << "THE END" << endl;
return 0;
}
我运行程序时的输出:
stream OPENED
BINARY DATA
0 5 54 0 0 62 72 0 1c 41 0 f 42 40 0 0
0 0 0 4 2f 76 53 0 0 3 e8 53 50 59 20 20
20 0 11 5 d0 0 1c 41 0 f 42 40 0 0 0 0
0 4 2f 78 42 0 0 3 e8 53 50 59 20 20 20 0
10 f7 5c 0 1c 41 0 f 42 40 0 0 0 0 0 4
2f 90 53 0 0 1 2c 53 50 59 20 20 20 0 11 2
b0 0 5 54 0 0 62 76 0 d 44 14 25 78 80 0
0 0 0 0 4 2f 90 0 d 44 14 25 78 80 0 0
Length: 500
Message type: T
Second: 726200
Length: 1c00
Message type: A
Timestamp: 40420f
OrderReferenceNumber: 53762f0400000000
BuySellIndicator:
Shares: 20595053
Stock:
Price: 420f0041
THE END
程序正确地将字节放入 Tmessage 结构中。(0 5 54 0 0 62 72)
但是,在解析 Amessage 时发生了一些事情。
(0 1c 41 0 f 42 40 0 0 0 0 0 4 2f 76 53 0 0 3 e8 53 50 59 20 20 20 0 11 5 d0)
Lenght、MessageType 和 Timestamp 是正确的,但 OrderReferenceNumber 包含属于 BuySellIndicator 的“53”字节,然后其他变量不正确。
正确的 A 消息输出应该是:
长度:1c 0
消息类型:41
时间戳:40 42 f 0
OrderReferenceNumber:76 2f 4 0 0 0 0 0
BuySellIndicator:53
Shares:e8 3 0 0
Stock:53 50 59 20 20 20
Price : d0 5 11 0
2 个问题:a) 为什么 OrderReferenceNumber 包含“53”字节?b) 我认为“char Stock[6]”不起作用,因为在 Share 的字节和 Price 的字节之间有超过 6 个字节。如何将 6 个字节放入 char 向量或字符串中?
注意:我知道我必须交换字节,因为二进制数据是大端的。这就是为什么不应该交换“股票”的原因。非常感谢您的帮助!亲切的问候,