尝试使用 Newtonsoft.Json 从 str1=X&str2=Y 中取出一个对象
获取:“解析值时遇到意外字符:s。第 1 行,位置 1。”
我是否期望这会起作用?
public class MyTest
{
public string str1 { get; set; }
public string str2 { get; set; }
}
public MyTest GetJson()
{
data = "str1=X&str2=Y";
JsonSerializerSettings jss = new JsonSerializerSettings();
jss.MissingMemberHandling = MissingMemberHandling.Error;
jss.ObjectCreationHandling = ObjectCreationHandling.Reuse;
MyTest myTest = JsonConvert.DeserializeObject<MyTest>(data, jss);
}