1

我正在尝试使用 Zend Framework 2 tableGateway 生成以下查询。 

SELECT 
dfsstamp, 
dfcstamp, 
df_rstrd_flg, 
dfctid, 
dfname, 
dfloc, 
dfdesc, 
dfcuser, 
dfmuser, 
dfid AS, 
t2.dfdfid, 
ctname, 
cafldnme, 
caid, 
atid, 
atvalue, 
t1.record_count
FROM 
(
    select * from dssdocflp 
    where dfdfid <= 1
) as t2
LEFT JOIN
(
    select dfdfid, count(*) as record_count from dssdocflp
    group by dfdfid having dfdfid > 1
) as t1
on t2.dfid = t1.dfdfid
INNER JOIN dsscfgtpp ON ctid = dfctid 
INNER JOIN dsscfgatp ON cactid = ctid 
INNER JOIN dssattrp ON atcaid = caid AND atdfid = dfid 
WHERE dfdbid = '33' 
ORDER BY dfcstamp DESC, dfid ASC, caseqno ASC

以下是我到目前为止所得到的

$select = $this->tableGateway
                   ->getSql()
                   ->select()
                   ->columns(array(
                        'dfsstamp' => new Expression('date(dfsstamp)'),
                        'dfcstamp' => new Expression('date(dfcstamp)'),
                        'df_rstrd_flg',
                        'dfctid',
                        'dfname',
                        'dfloc',
                        'dfdesc',
                        'dfcuser',
                        'dfmuser',
                        'dfid',
                        'dfdfid'
                        //'record_count'
                        ))
                    ->join('dsscfgtpp', 'ctid = dfctid', array('ctname'))
                    ->join('dsscfgatp', 'cactid = ctid', array('cafldnme', 'caid'))
                    ->join('dssattrp', 'atcaid = caid AND atdfid = dfid', array('atid', 'atvalue'))
                    ->where(dfdbid = 33)
                    ->order(array('dfcstamp DESC', 'dfid ASC', 'caseqno'))

我只需要让子查询的左连接就可以工作。我无法弄清楚我需要组合 from 和 join 方法的哪种组合。我现在已经挣扎了 3 个小时，尽管我会寻求帮助。任何帮助将不胜感激

根据@peterpeterson 的建议，这是我尝试的新查询

 $subselect_t2 = new Select();
    $subselect_t2->from('dssdocflp')
        ->where(array('dfdid <= 1'));

    $subselect_t1 = new Select();
    $subselect_t1->from('dssdocflp')
        ->columns(array(
            'dfdfid',
            'record_count' => new Expression('count(*)')
        ))
        ->group(array('dfdfid'))->having(array('dfdid > 1'));

    $select = $this->tableGateway
                   ->getSql()
                   ->select()
                   ->columns(array(
                        'dfcstamp',
                        'df_rstrd_flg',
                        'dfctid',
                        'dfname',
                        'dfloc',
                        'dfdesc',
                        'dfcuser',
                        'dfmuser',
                        'dfid',
                        'dfdfid',
                        't1.record_count'
                        ))
                    ->from(array('t2' => $subselect_t2))
                    ->join(array('t1' => $subselect_t1), 't2.dfid = t1.dfdid', array(), 'left')
                    ->join('dsscfgtpp', 'ctid = dfctid', array('ctname'))
                    ->join('dsscfgatp', 'cactid = ctid', array('cafldnme', 'caid'))
                    ->join('dssattrp', 'atcaid = caid AND atdfid = dfid', array('atid', 'atvalue'))
                    ->where($this->documentWhereClause->create($searchData))
                    ->order(array('dfcstamp DESC', 'dfid ASC', 'dfdfid DESC', 'caseqno'))
                    ->limit(500);

运行我运行它我得到以下错误：

由于此对象是在构造函数中使用表和/或模式创建的，因此它是只读的。

也许我仍然没有正确地形成查询。我正在使用 tableGateway。也许不可能通过 tableGateway 进行这种查询？

4

1 回答 1

0

根据下面的链接，您必须传递第三个参数：

$select::JOIN_LEFT

不确定，您可能需要保存变量：

$select = $this->tableGateway
                   ->getSql()
                   ->select();

然后做连接

Sql Join zf2

编辑

看来我看错了你的问题，这是你的做法：

<?php
$subselect = new Select;
$subselect->from('bar')->where->like('y', '%Foo%');
$select = new Select;
$select->from('foo')->join(array('z' => $select39subselect), 'z.foo = bar.id');

所以基本上创建另一个选择，然后将其传递给连接。

于 2015-09-23T16:04:07.970 回答