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我正在编写 SQL Server 2012 中的脚本（作为经典 ASP 页面的后端），以从我的初始表 ( aaa_test_ap) 中选择所有行并将它们分布在我的其他 3 个表 ( aaa_test_users、aaa_test_users_positions和aaa_test_users_education) 中。

我想获得 的标识aaa_test_users.ID，一旦将一行插入其中，用于其他两个表插入，作为它们的 FK ( User_ID)，在同一个查询中。

INSERT INTO是否可以在一个查询中 使用该方法获得身份？

我试过使用SCOPE_Identity()，但它只返回最后一个值。

使用该OUTPUT方法，我将如何利用它生成的表值，以便将第一个插入语句生成的值插入到接下来的两个语句中，每个语句都在正确的插入行中？

首先，表格：

CREATE TABLE [dbo].[aaa_test_sp]
(
    [ID] [int] IDENTITY(1,1) NOT NULL,
    [UserName] [nvarchar](50) NULL,
    [first_name] [nvarchar](50) NULL,
    [last_name] [nvarchar](50) NULL,
    [position] [nvarchar](50) NULL,
    [phone] [nvarchar](50) NULL,
    [education] [nvarchar](50) NULL,
    [ListID] [int] NULL,

    CONSTRAINT [PK_aaa_test_sp] 
       PRIMARY KEY CLUSTERED ([ID] ASC)
 ) ON [PRIMARY]
 GO

CREATE TABLE [dbo].[aaa_test_users]
(
    [UserID] [int] IDENTITY(1,1) NOT NULL,
    [UserName] [nvarchar](50) NULL,
    [first_name] [nvarchar](50) NULL,
    [last_name] [nvarchar](50) NULL,

    CONSTRAINT [PK_aaa_test_users] 
       PRIMARY KEY CLUSTERED ([UserID] ASC)
) ON [PRIMARY]
GO

CREATE TABLE [dbo].[aaa_test_users_positions]
(
    [ID] [int] IDENTITY(1,1) NOT NULL,
    [UserID] [int] NULL,
    [position] [nvarchar](50) NULL,
    [phone] [nvarchar](50) NULL,

    CONSTRAINT [PK_aaa_test_users_positions] 
        PRIMARY KEY CLUSTERED ([ID] ASC)
) ON [PRIMARY]
GO

CREATE TABLE [dbo].[aaa_test_users_education] 
(
    [ID] [int] IDENTITY(1,1) NOT NULL,
    [UserID] [int] NULL,
    [education] [nvarchar](50) NULL,

    CONSTRAINT [PK_aaa_test_users_education] 
        PRIMARY KEY CLUSTERED ([ID] ASC)
) ON [PRIMARY]
GO

这是我一直在处理的查询：

--declare @NewUserID nvarchar(50)
DECLARE @InsertOutput1 table (UserID nvarchar(50));

--insert, first, rows from sp to users, and get the autoNumber'ed ID,
--"NewUserID"
INSERT INTO aaa_test_users (UserName, first_name, last_name)
OUTPUT inserted.UserID INTO @InsertOutput1
    SELECT 
        UserName, first_name, last_name
    FROM aaa_test_sp
    WHERE (ListId = '1')

--select * from @InsertOutput1
--SELECT SCOPE_IDENTITY() As NewUserID
--set @NewUserID=(SELECT SCOPE_IDENTITY() )

--now that the "NewUserID" has been generated,
--insert it, along with other columns,
--into the 'users_positions' table.
--print 'new user id is ' + @NewUserID
INSERT INTO aaa_test_users_positions (UserID, position, phone)
    (SELECT 
         @NewUserID, position, phone
     FROM aaa_test_sp
     WHERE (ListId = '1')
    )

--now that the "NewUserID" has been generated,
--insert it, along with other columns,
--into the 'users_education' table 
--print @NewUserID
INSERT INTO aaa_test_users_education (UserID, education)
   (SELECT @NewUserID, education
    FROM aaa_test_sp
    WHERE (ListId = '1'))
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1 回答 1

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您加入新 ID 所在的表。

作为第二个插入的示例：

INSERT INTO aaa_test_users_positions(UserID, position, phone)
    SELECT io.UserID, position, phone
    FROM aaa_test_sp cross join
         @InsertOutput1 io
    WHERE ListId = '1';

注意：鉴于您的结构， 中可能只有一行@InsertOutput1，因此这不应产生比预期更多的行。

于 2015-09-18T22:59:04.730 回答