我有这种情况，其中一位访问者向居民创建了一个待处理的访问请求。然后根据居民提供的答复，访问被批准或拒绝。但在创建新请求之前，访客也有可能已获得居民的永久批准访问许可，在这种情况下，我不需要经历审批周期。
我想以一种可以使用继承的方式对我的实体进行建模，其中，待定访问请求关系是从访问者到居民创建的，而批准/不批准是从居民到访问者发生的。
这是通用的 Person 类：
public abstract class Person extends Entity {
@Property private String name;
@Property private String mobileNumber;
@Property private String emailAddress;
@Property private String aadhardId;
}
请注意，Entity 类与 spring-OGM 示例中的相同。这是一个设置了关系类型的居民：
@NodeEntity(label = "Resident")
public class Resident extends Person {
@Autowired
Session session;
@Relationship(type = "PENDING-VISIT", direction = Relationship.INCOMING)
Set<PendingVisit> pendingVisits = new HashSet<>();
@Relationship(type = "PERMANENTLY-APPROVED-VISIT", direction = Relationship.OUTGOING)
Set<PermanentlyApprovedVisit> permanentlyApprovedVisits = new HashSet<>();
和访客：
@NodeEntity(label="Visitor")
public class Visitor extends Person {
@Autowired
ResidentRepository residentRepository;
@Relationship(type = "PENDING-VISIT", direction = Relationship.OUTGOING)
private Set<PendingVisit> pendingVisit = new HashSet<>();
public Set<PendingVisit> getPendingVisits() {
return pendingVisit;
}
@Relationship(type = "PERMANENTLY-APPROVED-VISIT",direction = Relationship.INCOMING)
Set<PermanentlyApprovedVisit> permanentlyApprovedVisits = new HashSet<>();
以下是按顺序排列的通用访问、PendingVisit 和 PermanentlyApprovedVisit 关系：
公共抽象类访问{
@GraphId private Long visitId;
@StartNode private T visitRequester;
@EndNode private R visitResponder;
@Property private Date dov;
@RelationshipEntity(type="PENDING-VISIT")
public class PendingVisit extends Visit<Visitor, Resident> {
public PendingVisit(Visitor visitor, Resident resident){
super(visitor,resident);
}
}
@RelationshipEntity(type="PERMANENTLY-APPROVED-VISIT")
public class PermanentlyApprovedVisit extends Visit<Resident,Visitor> {
private final boolean permanentlyApproved = true;
public PermanentlyApprovedVisit(Resident resident, Visitor visitor){
super(resident,visitor);
}
}
在尝试创建 pendingVisit 时，我首先要检查 PErmanentlyApprovedVisit 关系是否已经存在。我正在编写测试，这就是我测试的方式：
Optional<PermanentlyApprovedVisit> permanentlyApprovedVisit = Optional.ofNullable(residentRepository.findIfVistorApprovedPermanentlyByResident(resident.getId(), this.getId()));
if(permanentlyApprovedVisit.isPresent())
return permanentlyApprovedVisit.get();
最后，这是 ResidentRepository 方法：
@Query(" OPTIONAL MATCH (resident:Resident)-[r:PERMANENTLY-APPROVED-VISIT]→(visitor:Visitor)"+
" WHERE resident.id = {residentId} AND visitor.id = {visitorId}"+
"RETURN r")
public PermanentlyApprovedVisit findIfVistorApprovedPermanentlyByResident(@Param("residentId")long residentId, @Param("visitorId") long visitorId);
但是，当我运行它时，我不断收到这个异常：
org.neo4j.ogm.session.result.ResultProcessingException: Could not initialise res
ponse
at org.neo4j.ogm.session.response.JsonResponse.parseErrors(JsonResponse.
java:165)
at org.neo4j.ogm.session.response.JsonResponse.parseColumns(JsonResponse
.java:139)
at org.neo4j.ogm.session.response.JsonResponse.initialiseScan(JsonRespon
se.java:75)
at org.neo4j.ogm.session.response.GraphModelResponse.initialiseScan(Grap
hModelResponse.java:69)
at org.neo4j.ogm.session.response.GraphModelResponse.<init>(GraphModelRe
sponse.java:39)
at org.neo4j.ogm.session.request.SessionRequestHandler.execute(SessionRe
questHandler.java:57)
at org.neo4j.ogm.session.delegates.ExecuteQueriesDelegate.executeAndMap(
ExecuteQueriesDelegate.java:118)
at org.neo4j.ogm.session.delegates.ExecuteQueriesDelegate.query(ExecuteQ
ueriesDelegate.java:76)
at org.neo4j.ogm.session.delegates.ExecuteQueriesDelegate.queryForObject
(ExecuteQueriesDelegate.java:50)
at org.neo4j.ogm.session.Neo4jSession.queryForObject(Neo4jSession.java:3
30)
at org.springframework.data.neo4j.repository.query.GraphRepositoryQuery.
execute(GraphRepositoryQuery.java:73)
at org.springframework.data.neo4j.repository.query.GraphRepositoryQuery.
execute(GraphRepositoryQuery.java:50)
at org.springframework.data.repository.core.support.RepositoryFactorySup
port$QueryExecutorMethodInterceptor.doInvoke(RepositoryFactorySupport.java:431)
at org.springframework.data.repository.core.support.RepositoryFactorySup
port$QueryExecutorMethodInterceptor.invoke(RepositoryFactorySupport.java:409)
at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(
ReflectiveMethodInvocation.java:179)
at org.springframework.data.projection.DefaultMethodInvokingMethodInterc
eptor.invoke(DefaultMethodInvokingMethodInterceptor.java:61)
at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(
ReflectiveMethodInvocation.java:179)
at org.springframework.transaction.interceptor.TransactionInterceptor$1.
proceedWithInvocation(TransactionInterceptor.java:99)
at org.springframework.transaction.interceptor.TransactionAspectSupport.
invokeWithinTransaction(TransactionAspectSupport.java:281)
at org.springframework.transaction.interceptor.TransactionInterceptor.in
voke(TransactionInterceptor.java:96)
at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(
ReflectiveMethodInvocation.java:179)
at org.springframework.dao.support.PersistenceExceptionTranslationInterc
eptor.invoke(PersistenceExceptionTranslationInterceptor.java:136)
at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(
ReflectiveMethodInvocation.java:179)
at org.springframework.aop.framework.JdkDynamicAopProxy.invoke(JdkDynami
cAopProxy.java:207)
at com.sun.proxy.$Proxy106.findIfVistorApprovedPermanentlyByResident(Unk
nown Source)
at visit.domain.Visitor.sendPendingVisitRequest(Visitor.java:62)
at visit.domain.DomainTests.shouldCreatePendingVisit(DomainTests.java:89
)
我想在这里实现的那种建模有问题吗？我读了另一个线程，这是 Prev 和 Next 的问题：