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所以我想创建一个简单的程序，使用 time.monotonic() 函数在用户输入短语之前和之后进行提示，然后给出每分钟的平均单词以及输入短语所花费的总秒数。

短语：“敏捷的棕色狐狸跳过懒惰的狗”

我是编程新手，所以我会在下面给出我的代码和粗略的想法，请随时纠正我。感谢所有帮助。

import time 

inputText = str(input('Enter the phrase :"The quick brown fox jumps over the lazy dog" as fast as possible')

t0 = time.time() #start time
t1 = time.time() #stop time

timeTaken = t1 - t0
wordPM = (9/timeTaken)

#print time taken in seconds and avg WPM

好的，所以我接受了第一张海报的建议，但是当我在输入 yes 后运行代码以继续时，它会停止并且没有错误，所以我不确定出了什么问题。

import time 
string = "The quick brown fox jumps over the lazy dog"
word_count = len(string.split())

while str(input('Enter "yes" when you are ready')) != 'yes':
str(input('Enter "yes" when you are ready'))
t0 = time.time() #start time
inputText = str(input('Enter the phrase :"The quick brown fox jumps over the lazy dog" as fast as possible' % string))
t1 = time.time() #stop time  
acc = len(set(inputText.split()) & set(string.split()))
acc = acc/word_count
timeTaken = t1 - t0
wordPM = (word_count/timeTaken)
print (wordPM, acc)
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1 回答 1

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import time 
string = "The quick brown fox jumps over the lazy dog"
word_count = len(string.split())

您可以为用户准备一些介绍

while str(raw_input('Enter "yes" when you are ready')) <> 'yes':
    str(raw_input('Enter "yes" when you are ready'))

然后你开始你的计时器

t0 = time.time() #start time
inputText = str(raw_input('Enter the phrase :"%s" as fast as possible' % string))
t1 = time.time() #stop time

然后你可以以某种方式计算正确输入单词的百分比

acc = len(set(inputText.split()) & set(string.split()))
acc = acc/word_count

timeTaken = t1 - t0
wordPM = (word_count/timeTaken)
print wordPM, acc
于 2015-09-17T01:56:42.137 回答