0

你应该如何有条件地添加一个像我下面这样的元素?如果道具为真,我只想<div className='next-field__connected-wrapper'>存在于其中。withFilter

  render: function () {
    if (this.props.withFilter) {
      return (
        <div>
          <div className='next-card next-card__section next-card__section--no-bottom-spacing'>
            <div className='next-field__connected-wrapper'>
              { this.props.children }
            </div>
          </div>
        </div>
      )
    } else {
      return (
        <div>
          <div className='next-card next-card__section next-card__section--no-bottom-spacing'>
            { this.props.children }
          </div>
        </div>
      )
    }
  }
4

1 回答 1

2

请记住,JSX 元素只是 JavaScript 对象,您可以将它们分配给变量并像其他任何东西一样传递它们:

render: function () {
  let inner = this.props.children;

  if (this.props.withFilter) {
    inner = (
      <div className='next-field__connected-wrapper'>
        {inner}
      </div>
    );
  }

  return (
    <div>
      <div className='next-card next-card__section next-card__section--no-bottom-spacing'>
        {inner}
      </div>
    </div>
  );
}
于 2015-09-15T23:08:16.830 回答