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我在最初使用 (protocol=0) 格式腌制的多个子目录中有一个包含 170,000 多个腌制文件的目录。这在时间或空间方面都不是很有效。

我编写了一个脚本来重新腌制（使用 cPickle，协议 = 2）文件夹中的每个文件，但奇怪的是，该脚本在处理特定文件（文件 # 95,000）时抛出异常。最初，我认为泡菜文件已损坏。当我尝试从 IPython 命令行加载这个确切的泡菜文件时，文件加载得很好。

所以，我对为什么会发生这种情况感到目瞪口呆。这是我的脚本，感谢您的帮助：

import os
import cPickle
import numpy
import time
import re
from progressbar import ProgressBar

inpath = '/path/to/folder'



def list_files(dir):                                                                                                
    r = []                                                                                                           
    subdirs = [x[0] for x in os.walk(dir)]                                                                            
    for subdir in subdirs:                                                                                            
        files = os.walk(subdir).next()[2]                                                                             
        if (len(files) > 0):                                                                                          
            for file in files:                                                                                        
                r.append(subdir + "/" + file)                                                                        
    return r     



infileList = list_files(inpath)
print "Total number of files found: %d" % len(infileList)
print "\n\n"

progress = ProgressBar()

outfilename = " "

print "Processing pickle files. Pls wait..."
t0 = time.time()
filecount = 0

for file in progress(infileList):
    try:
        arr = cPickle.load(open(file , "rb" ))
        outfilename = re.sub('/initial/path/','/new/path/',file)

        if not os.path.exists(os.path.dirname(outfilename)):
            os.makedirs(os.path.dirname(outfilename))
        with open(outfilename, "wb") as f:
            cPickle.dump(arr,f,protocol=2)

        filecount = filecount + 1


    except Exception,e:

        print "\n" + str(filecount)
        print "\nError occured while processing file: " +  outfilename 
        tx = time.time()
        print "\n Time elapsed: %.2f" % (tx-t0)
        continue

t1 = time.time()

total = t1-t0

print "Files repickled with protocol=2.\nRepickling execution time: %.2f sec" % total

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