7

我有一个 JSON 响应,它是一个哈希数组:

[{"project" => {"id" => 1, "name" => "Internal"},
 {"project" => {"id" => 2, "name" => "External"}}]

我的代码如下所示:

client = HTTP::Client.new(url, ssl: true)
response = client.get("/projects", ssl: true)
projects = JSON.parse(response.body) as Array

这给了我一个 Array 但似乎我需要对元素进行类型转换才能实际使用它们,否则我会得到undefined method '[]' for Nil (compile-time type is (Nil | String | Int64 | Float64 | Bool | Hash(String, JSON::Type) | Array(JSON::Type))).

我试过as Array(Hash)了,但这给了我can't use Hash(K, V) as generic type argument yet, use a more specific type

如何指定类型?

4

2 回答 2

10

You have to cast these as you access the elements:

projects = JSON.parse(json).as(Array)
project = projects.first.as(Hash)["project"].as(Hash)
id = project["id"].as(Int64)

http://carc.in/#/r/f3f

But for well structured data like this you're better off with using JSON.mapping:

class ProjectContainer
  JSON.mapping({
    project: Project
  })
end

class Project
  JSON.mapping({
    id: Int64,
    name: String
  })
end

projects = Array(ProjectContainer).from_json(json)
project = projects.first.project
pp id = project.id

http://carc.in/#/r/f3g

You can see a slightly more detailed explanation of this problem at https://github.com/manastech/crystal/issues/982#issuecomment-121156428

于 2015-09-13T18:06:34.473 回答
3

You continue casting in every step:

projects = JSON.parse(response.body) as Array
projects.each do |project|
  project = project as Hash
  project = project["project"] as Hash
  id = project["id"] as Int
  name = project["name"] as String
end

But if your API response has a well-known structure, I strongly suggest you use JSON.mapping: https://crystal-lang.org/api/0.22.0/JSON.html#mapping-macro

于 2015-09-13T18:08:27.823 回答