3

我正在实现谷歌提供的应用索引 API。如此处所示，我在 onStart() 方法中连接了客户端，如下所示：

APP_URI = Uri.parse(baseAppUri + slug);
    WEB_URL = Uri.parse(baseWebUri + slug);
    Action viewAction = Action.newAction(Action.TYPE_VIEW, title, WEB_URL, APP_URI);

    // Call the App Indexing API start method after the view has
    // completely
    // rendered
    // Call the App Indexing API view method
    PendingResult<Status> result = AppIndex.AppIndexApi.start(mClient, viewAction);

    result.setResultCallback(new ResultCallback<Status>() {
        @Override
        public void onResult(Status status) {
            if (status.isSuccess()) {
                CommonLib.ZLog(TAG, "App Indexing API: Recorded " + title + " view successfully.");
            } else {
                Log.e(TAG, "App Indexing API: There was an error recording the view." + status.toString());
            }
        }
    });

在用户完成页面后，即用户按下后退按钮，我在 onStop() 中调用 AppIndexApi.end，如下所示：

@Override
protected void onStop() {

    // Call end() and disconnect the client
    Action viewAction = Action.newAction(Action.TYPE_VIEW, title, APP_URI);
    PendingResult<Status> result = AppIndex.AppIndexApi.end(mClient, viewAction);

    result.setResultCallback(new ResultCallback<Status>() {
        @Override
        public void onResult(Status status) {
            if (status.isSuccess()) {
                Log.d(TAG, "App Indexing API: Recorded " + title + " view end successfully.");
            } else {
                Log.e(TAG, "App Indexing API: There was an error recording the  view." + status.toString());
            }
        }
    });

    mClient.disconnect();
    super.onStop();

}

问题是回调没有被执行。resultcallback 中的所有情况都没有记录状态并且执行直接跳转到mClient.disconnect.

并且标题没有显示在谷歌应用程序的搜索结果中。

知道我在哪里出错了吗？

4

1 回答 1

0

请尝试逐步调试您的应用程序。我遇到了类似的问题，调试帮助我发现在其他一些代码中发生了一些异常，因此没有发生回调

于 2015-09-12T09:59:24.597 回答