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我正在尝试完成以下任务：

让所有发送到我的域的电子邮件都解析其收件人、正文、主题行和...的内容，以便我从中构造一个传真对象并将其作为传真发送

到目前为止，我已经能够将我的 MX 记录设置为指向 Sendgrid，并使用 Ngrok 从 Sendgrid 的 Parse API 中获得回调在我的本地主机服务器中。下一步是将原始对象转换为我可以使用的对象。这将我带到了 Thoughbot 的Griddler Gem。

到目前为止，这就是我设置我的应用程序的方式：

Sendgrid 设置： URL：https://8c00fab0.ngrok.io/email_processor | 垃圾邮件检查和发送原始邮件都被检查

如前所述，这部分有效，因为我确实收到了这个：

Parameters: {"dkim"=>"{@gmail.com : pass}", "email"=>"Received: by mx0034p1mdw1.sendgrid.net with SMTP id 253FfvZ40f Wed, 09 Sep 2015 22:31:48 +0000 (UTC)\nReceived: from mail-qg0-f54.google.com (mail-qg0-f54.google.com [209.85.192.54]) by mx0034p1mdw1.sendgrid.net (Postfix) with ESMTPS id 63848A83017 for <14085552422@faxbyemail.co>; Wed,  9 Sep 2015 22:31:48 +0000 (UTC)\nReceived: by qgx61 with SMTP id 61so21251135qgx.3 for <14085552422@faxbyemail.co>; Wed, 09 Sep 2015 15:31:48 -0700 (PDT)\nDKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:from:date:message-id:subject:to:content-type; bh=Wo6p7CSlR30aGxf5SwjuZ2klt31URDqTZUHrKdmLz7s=; b=fWfFOQ4YOtijYvphYL9/1shyzK8CBTcHS37s89t9Qn4xK8OrXwVKtmGtNnwg7a1n48 JHkEeAdxVvRMpinxPllGiJoPNy0ivVN36uEYbsrLTcZVlx9RIIl8u5PjmrE1aqlnkjPy gOcbfJunVCFZLaLpv3RB/GiNYL1bodgW7nn8sMTmwN5EwoH7SncS7cle4ksPadgiGv9f DVoJniX2yuMqygSVLT4Qrk4JDzR6G2oj1Fz3QkcrQfNKxOS6iyBhpnh3cDuUi8GTSVYl Nqq2dtKlUNqI+U9ojtG1BjGVUKbP0v5apF3Wvmj72p8L0AB3FHqL8uvFnhi2dGTFVq+y 6nUQ==\nX-Received: by 10.140.233.137 with SMTP id e131mr48879201qhc.37.1441837907953; Wed, 09 Sep 2015 15:31:47 -0700 (PDT)\nMIME-Version: 1.0\nFrom: Sam Sedighian <samansb@gmail.com>\nDate: Wed, 09 Sep 2015 22:31:38 +0000\nMessage-ID: <CAEMkzYbhsLLB3NPLznG+-RibP5kzDG5yTT++mQL1ep-vH6_orA@mail.gmail.com>\nSubject: test 20\nTo: \"14085552422@faxbyemail.co\" <14085552422@faxbyemail.co>\nContent-Type: multipart/alternative; boundary=001a11354d8053d2d1051f580c22\n\n--001a11354d8053d2d1051f580c22\nContent-Type: text/plain; charset=UTF-8\n\nbody etxt\n\n--001a11354d8053d2d1051f580c22\nContent-Type: text/html; charset=UTF-8\n\n<div dir=\"ltr\">body etxt</div>\n\n--001a11354d8053d2d1051f580c22--\n", "to"=>"\"14085552422@faxbyemail.co\" <14085552422@faxbyemail.co>", "from"=>"Sam Sedighian <samansb@gmail.com>", "sender_ip"=>"209.85.192.54", "spam_report"=>"Spam detection software, running on the system \"mx0034p1mdw1.sendgrid.net\", has\nidentified this incoming email as possible spam.  The original message\nhas been attached to this so you can view it (if it isn't spam) or label\nsimilar future email.  If you have any questions, see\n@@CONTACT_ADDRESS@@ for details.\n\nContent preview:  body etxt body etxt [...] \n\nContent analysis details:   (0.0 points, 5.0 required)\n\n pts rule name              description\n---- ---------------------- --------------------------------------------------\n 0.0 FREEMAIL_FROM          Sender email is freemail (samansb[at]gmail.com)\n 0.0 HTML_MESSAGE           BODY: HTML included in message\n 0.0 T_MIME_NO_TEXT         No text body parts\n\n", "envelope"=>"{\"to\":[\"14085552422@faxbyemail.co\"],\"from\":\"samansb@gmail.com\"}", "subject"=>"test 20", "spam_score"=>"0.012", "charsets"=>"{\"to\":\"UTF-8\",\"subject\":\"UTF-8\",\"from\":\"UTF-8\"}", "SPF"=>"pass"}

宝石文件

gem 'griddler'
gem 'griddler-sendgrid'

Gemfile.lock

griddler (1.2.1)
  htmlentities
  rails (>= 3.2.0)
griddler-sendgrid (0.0.1)
  griddler

路线.rb

post '/email_processor' => 'fax#sendgrid'
# this corresponds to the following route when I rake route:
# email_processor POST   /email_processor(.:format) fax#sendgrid

配置/初始化程序/griddler.rb

Griddler.configure do |config|
  config.processor_class = EmailProcessor
  config.processor_method = :process
  config.reply_delimiter = '-- REPLY ABOVE THIS LINE --'
  config.email_service = :sendgrid
end

应用程序/控制器/fax_controller.rb

def sendgrid
  EmailProcessor.new(params).process
end

应用程序/模型/email_processor.rb

class EmailProcessor

  def initialize(email)
    @email = email
    @from = email.from
    @body = email.body
  end

  def self.process(email)
    Fax.create({params go here})
  end

end

我最终给出了 Completed 500 Internal server error - 因为我没有将 200 OK 回传给 Sendgrid，但重要的是我在日志中收到以下错误：

NoMethodError (undefined method `from' for #<ActionController::Parameters:0x007fc742a33070>):
  app/models/email_processor.rb:5:in `initialize'
  app/controllers/fax_controller.rb:31:in `new'
  app/controllers/fax_controller.rb:31:in `sendgrid'
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2 回答 2

1

The way I do this in Rails is to gather the email params in the Controller.

For instance, in a sample app I created, people email selfies to our Parse API. In my selfie_controller.rb, I have a route '/inbound' and I have the following:

def inbound

    if !params['attachment1'].nil? and params['attachment1'].content_type == "image/jpeg"

        Selfy.create!({ pic: params['attachment1'], email: params['from'] })

    end

end

The call to Selfy.create! uses the selfy.rb model, but I gather the params from the email to send to that from the controller.

Is this something you could try?

于 2015-09-11T10:49:38.330 回答
1

我认为问题在于您绕过了 Griddler 在控制器端所做的工作。您将 Sendgrid 指向您自己创建的控制器和操作。相反，我认为您想指向 Griddler 的控制器和操作。请参阅“安装”下的自述文件。

改变你routes.rb是：

# your own route
# post '/email_processor' => 'fax#sendgrid'

# griddler's
post '/email_processor' => 'griddler/emails#create'

如果你看一下 Griddler 的控制器，你会发现它可以为你做一些事情来将东西放入你的电子邮件处理器类。

于 2015-10-01T18:21:18.260 回答