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我对此进行了搜索，但无法更正我的查询。在这方面需要帮助。这是我的 VU360User

@Entity
public class VU360User extends AuditedEntity implements UserDetails, CredentialsContainer, Cloneable {
    ...
    private Learner learner;
    private Set<LmsRole> lmsRoles;
    ...

    @OneToOne(mappedBy = "vu360User", fetch=FetchType.LAZY)
    public Learner getLearner() {
        return learner;
    }
    //Setter

    @ManyToMany(fetch=FetchType.LAZY)
    @JoinTable(
        name = "VU360USER_ROLE", 
        joinColumns = { 
            @JoinColumn(name = "USER_ID", referencedColumnName = "ID") 
        }, 
        inverseJoinColumns = { 
            @JoinColumn(name = "ROLE_ID", referencedColumnName = "ID") 
        }
    )
    public Set<LmsRole> getLmsRoles() {
        return lmsRoles;
    }
    //Setter

}

这是我的 LmsRole 课程

@Entity
public class LmsRole extends BaseEntity implements GrantedAuthority  {
    ....
    private List<LmsRoleLmsFeature> lmsRoleLmsFeature;

    @OneToMany(mappedBy = "lmsRole", fetch=FetchType.LAZY)
    public List<LmsRoleLmsFeature> getLmsRoleLmsFeature() {
        return lmsRoleLmsFeature;
    }

    public void setLmsRoleLmsFeature(List<LmsRoleLmsFeature> lmsRoleLmsFeature) {
        this.lmsRoleLmsFeature = lmsRoleLmsFeature;
    }
    ...
}

这是我的 LmsRoleLmsFeature 类

@Entity
public class LmsRoleLmsFeature extends BaseEntity implements Serializable{
    ...
    private LmsRole lmsRole;
    private LmsFeature lmsFeature;

    @ManyToOne(fetch=FetchType.LAZY)
    @JoinColumn(name="LMSROLE_ID")
    public LmsRole getLmsRole() {
        return lmsRole;
    }

    @ManyToOne(fetch=FetchType.LAZY)
    @JoinColumn(name="LMSFEATURE_ID")
    public LmsFeature getLmsFeature() {
        return lmsFeature;
    }
    ...
}

现在这是我正在尝试进行但遇到异常的查询

@Query("select distinct u, l, c, d, ta, la, p, ra, i from #{#entityName} u, IN (u.lmsRoles) lr "
        + "join fetch u.learner l "
        + "join fetch l.customer c "
        + "join fetch c.distributor d "
        + "join fetch u.trainingAdministrator ta "
        + "join fetch u.lmsAdministrator la "
        + "join fetch u.proctor p "
        + "join fetch u.regulatoryAnalyst ra "
        + "join fetch u.instructor i "
        + "join u.lmsRoles.lmsRoleLmsFeature lrlf "
        //+ "join lr.lmsRoleLmsFeature lrlf "
        + "where u.username = :userName and c.activeTf = true and d.status = true")
VU360User findByUserNameWithAllEntitiesAssociations(@Param("userName")String userName);

我收到以下异常

Caused by: org.hibernate.QueryException: illegal attempt to dereference collection [vu360user0_.id.lmsRoles] with element property reference [lmsRoleLmsFeature]

我试过加入，但我无法做到。我尝试了不同的设置，但无法解决。请帮忙。

谢谢

4

1 回答 1

0

vu360user0_.id.lmsRoles是一个集合。因此，它没有名为的属性lmsRoleLmsFeature。

您不能在表达式中join u.lmsRoles.lmsRoleLmsFeature lrlf使用 Collection ( lmsRoles)，但您可以将其拆分为新的 JOIN 操作：

join u.lmsRoles lmsRoles
join lmsRoles.lmsRoleLmsFeature lrlf

那么，您是否需要重写您的 JPQL，如下所示：

@Query("select distinct u, l, c, d, ta, la, p, ra, i from #{#entityName} u, IN (u.lmsRoles) lr "
        + "join fetch u.learner l "
        + "join fetch l.customer c "
        + "join fetch c.distributor d "
        + "join fetch u.trainingAdministrator ta "
        + "join fetch u.lmsAdministrator la "
        + "join fetch u.proctor p "
        + "join fetch u.regulatoryAnalyst ra "
        + "join fetch u.instructor i "
        + "join fetch u.instructor i "
        + "join u.lmsRoles lmsRoles"
        + "join lmsRoles.lmsRoleLmsFeature lrlf"
        + "where u.username = :userName and c.activeTf = true and d.status = true")
VU360User findByUserNameWithAllEntitiesAssociations(@Param("userName")String userName);

并且要小心这个数量JOIN FETCH。这将生成一个大查询，结果中包含大量重复信息。

于 2015-11-23T14:25:29.910 回答