4

我正在使用 spring data JPA 1.8.2 并试图获得最佳结果。我正在使用以下方法

LearningSession findTopBySourceAndExternalLmsSessionIdAndCourseCodeAndLearnerEnrollmentEnrollmentStatusOrderByIdAsc(String source, String externalLmsSessionId, String courseCode, String enrollmentStatus);

我也尝试通过删除 OrderBy

LearningSession findTopBySourceAndExternalLmsSessionIdAndCourseCodeAndLearnerEnrollmentEnrollmentStatus(String source, String externalLmsSessionId, String courseCode, String enrollmentStatus);

在这两种情况下，hibernate 都会生成以下查询。只是*用于每件事。最后订购order by learningse0_.id asc

select TOP ?  learningse0_.*
from LearningSession learningse0_ 
left outer join LearnerEnrollment learnerenr1_ on learningse0_.ENROLLMENT_ID=learnerenr1_.id 
where learningse0_.source=?
and learningse0_.externalLmsSessionId=?
and learningse0_.courseCode=?
and learnerenr1_.enrollmentStatus=?

查询是正确的但我得到以下异常

Hibernate: select TOP ?  learningse0_.id as id1_47_, learningse0_.brandName as brandNam2_47_, learningse0_.courseApprovalId as courseAp3_47_, learningse0_.courseCode as courseCo4_47_, learningse0_.endTime as endTime5_47_, learningse0_.externalLmsSessionId as external6_47_, learningse0_.externalLmsUrl as external7_47_, learningse0_.isCourseMessageDisplay as isCourse8_47_, learningse0_.LANGUAGE_ID as LANGUAG15_47_, learningse0_.LEARNER_ID as LEARNER16_47_, learningse0_.ENROLLMENT_ID as ENROLLM17_47_, learningse0_.learningSessionGuid as learning9_47_, learningse0_.lmsProvider as lmsProv10_47_, learningse0_.redirectUrl as redirec11_47_, learningse0_.source as source12_47_, learningse0_.startTime as startTi13_47_, learningse0_.uniqueUserGuid as uniqueU14_47_ from LearningSession learningse0_ left outer join LearnerEnrollment learnerenr1_ on learningse0_.ENROLLMENT_ID=learnerenr1_.id where learningse0_.source=? and learningse0_.externalLmsSessionId=? and learningse0_.courseCode=? and learnerenr1_.enrollmentStatus=? order by learningse0_.id asc
13:53:47.686 [main] DEBUG org.hibernate.engine.jdbc.spi.SqlExceptionHelper - could not extract ResultSet [n/a]
com.microsoft.sqlserver.jdbc.SQLServerException: Incorrect syntax near '@P0'          
com.microsoft.sqlserver.jdbc.SQLServerException.makeFromDatabaseError(SQLServerException.java:216) ~[sqljdbc4-4.0.jar:?]

我做错了什么？我试过First, Top1，First1但结果是错误的。请帮忙。

谢谢

4

2 回答 2

8

不确定这是否对您有用，但是我遇到了同样的错误，经过大量挖掘后，我发现我在 JpaVendorAdapter 中使用了 SqlServerDialect，当我将其更改为更专门针对 SqlServer2012 (SqlServerDialect2012) 时出现错误走了：

<bean id="jpaVendorAdapter"
    class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter">
    <property name="database" value="SQL_SERVER" />
    <property name="databasePlatform" value="org.hibernate.dialect.SQLServer2012Dialect" />
    <property name="showSql" value="true" />
</bean>
于 2015-11-23T23:23:45.470 回答
0

我对 Hibernate 5 + Spring Data 也有同样的问题。将方言更改为 SQLServer2012方言对我有用。

公共类 SQLServerNativeDialect 扩展 SQLServer2012Dialect

供参考：： https ://hibernate.atlassian.net/browse/HHH-10032

谢谢，

于 2016-08-18T10:50:02.743 回答