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我在我的应用程序中添加了一个 segue，当我触发 segue 时，应用程序在 iPhone 5S 模拟器中崩溃（在其他模拟器中，由于设备特定的代码，它在此之前崩溃。这是问题的链接），消息“致命错误：在展开可选值时意外发现 nil”被打印到控制台，并且错误Thread 1: EXC_BAD_INSTRUCTION (code=EXC_1386_INVOP, subcode=0x0)显示在初始化数组的行上。我认为原因是因为我有一个UIImageView需要展开的 s 动画。这是我的做法：

// dieImages are UIImageViews that I am animating then displaying a random image of a die

    let dieImages = [dieImage0, dieImage1, dieImage2, dieImage3, dieImage4, dieImage5, dieImage6, dieImage7]

// Die animation
                for die in dieImages {
                    die.animationImages = [  <====== Error on this line
                        UIImage(named: "dicey-die2")!,
                        UIImage(named: "dicey-die6")!,
                        UIImage(named: "dicey-die1")!,
                        UIImage(named: "dicey-die4")!,
                        UIImage(named: "dicey-die3")!,
                        UIImage(named: "dicey-die5")!,
                        UIImage(named: "dicey-die3")!,
                        UIImage(named: "dicey-die1")!,
                        UIImage(named: "dicey-die6")!,
                        UIImage(named: "dicey-die3")!,
                        UIImage(named: "dicey-die5")!,
                        UIImage(named: "dicey-die2")!,
                        UIImage(named: "dicey-die4")!
                    ]

                die.animationRepeatCount = 1
                die.animationDuration = 1.0
            }

但是 segue 是类型AnyObject，所以我认为这就是 unwrapping 不起作用的原因：

override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {}

如何安全地解开图像，或者当 segue 被触发时根本不解开？我已经看到使用两个问号的方法（但这会导致“找不到接受提供的参数的 'init' 的重载”的错误）或 if 语句，但我不知道如何实现它。

更新

我尝试了这段代码，并且发生了和以前一样的事情

        let image0 = UIImage(named: "dicey-die1")!
        let image1 = UIImage(named: "dicey-die2")!
        let image2 = UIImage(named: "dicey-die3")!
        let image3 = UIImage(named: "dicey-die4")!
        let image4 = UIImage(named: "dicey-die5")!
        let image5 = UIImage(named: "dicey-die6")!

        let dieImages = [dieImage0, dieImage1, dieImage2, dieImage3, dieImage4, dieImage5, dieImage6, dieImage7]

        for die in dieImages {
            die.animationImages = [
                image1,
                image5,
                image0,
                image3,
                image2,
                image4,
                image2,
                image0,
                image5,
                image2,
                image4,
                image1,
                image2
            ]

            die.animationRepeatCount = 1
            die.animationDuration = 1.0
        }

更新 2

我创建了一个包含所有图像的数组

let image0:[UIImage] = [ UIImage(named: "dicey-die2")!,
            UIImage(named: "dicey-die6")!,
            UIImage(named: "dicey-die1")!,
            UIImage(named: "dicey-die4")!,
            UIImage(named: "dicey-die3")!,
            UIImage(named: "dicey-die5")!,
            UIImage(named: "dicey-die3")!,
            UIImage(named: "dicey-die1")!,
            UIImage(named: "dicey-die6")!,
            UIImage(named: "dicey-die3")!,
            UIImage(named: "dicey-die5")!,
            UIImage(named: "dicey-die2")!,
            UIImage(named: "dicey-die3")!]

然后我在动画中使用了数组

for die in dieImages {
    die.animationImages = [
      image0
    ]

应用程序崩溃了，AppDelegate所以我添加了一个异常断点，崩溃发生在动画数组上：

die.animationImages = [

这条消息被打印到控制台：

2015-09-08 07:23:05.192 Diced[80843:14927078] -[Swift._SwiftDeferredNSArray _isResizable]: unrecognized selector sent to instance 0x7fa738dd7460
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1 回答 1

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最好的选择是图像不可用。

一个简单的测试，这个工作并实例化图像：

let image = UIImage(named: "dicey-die2")!

如果不是，您如何将图像添加到项目中？

于 2015-09-07T18:52:19.770 回答