我正在尝试编写一个具有任意数量参数的函数。这些参数可以是 Int 或 String。我对整数有疑问。出于某种原因(我不明白),值 1 成为歧义的来源。如何处理这个错误,它的根源是什么?
{-# LANGUAGE FlexibleInstances #-}
import Data.Typeable
data PackArgTypes = PackInt Int | PackString String
deriving Show
class PackArg t where
toPackArg :: t -> PackArgTypes
instance PackArg Int where
toPackArg = PackInt . fromIntegral
instance PackArg Integer where
toPackArg = PackInt . fromIntegral
instance PackArg String where
toPackArg = PackString
class PackType t where
pack' :: String -> [PackArgTypes] -> t
instance PackType (IO a) where
pack' fmt acc = do
print fmt
mapM_ print acc
return undefined
instance (PackArg a, PackType r) => PackType (a -> r) where
pack' fmt acc = \x -> pack' fmt $ acc ++ [toPackArg x]
pack :: (PackType t) => String -> t
pack fmt = pack' fmt []
main :: IO ()
main = do
pack "asd" "qwe" "asd"(1 :: Int) -- Ok
pack "asd" "qwe" "asd" 1 -- Sad
在上述情况下,我遇到了错误
test1.hs:33:3-6: No instance for (PackArg a0) arising from a use of ‘pack’ …
The type variable ‘a0’ is ambiguous
Note: there are several potential instances:
instance PackArg String
-- Defined at /home/knesterov/test1.hs:13:10
instance PackArg Int -- Defined at /home/knesterov/test1.hs:10:10
In a stmt of a 'do' block: pack "asd" "qwe" "asd" 1
In the expression: do { pack "asd" "qwe" "asd" 1 }
In an equation for ‘main’: main = do { pack "asd" "qwe" "asd" 1 }
test1.hs:33:26: No instance for (Num a0) arising from the literal ‘1’ …
The type variable ‘a0’ is ambiguous
Note: there are several potential instances:
instance Num Double -- Defined in ‘GHC.Float’
instance Num Float -- Defined in ‘GHC.Float’
instance Integral a => Num (GHC.Real.Ratio a)
-- Defined in ‘GHC.Real’
...plus 7 others
In the fourth argument of ‘pack’, namely ‘1’
In a stmt of a 'do' block: pack "asd" "qwe" "asd" 1
In the expression: do { pack "asd" "qwe" "asd" 1 }
Compilation failed.
编辑
感谢 user5402 指出了 ghci 和 ghc 之间的区别。Ghci默认启用扩展 ExtendedDefaultRules
因此,加上三行,我的示例可以正常工作。
{-# LANGUAGE ExtendedDefaultRules #-}
instance PackArg Integer where
toPackArg = PackInt . fromIntegral