我正在使用以下控制器，以便在dashboard页面中 android 后退按钮退出应用程序，但在其余页面上它会返回。由于在dashboard页面之前我有一个教程，我只向我的用户展示一次，然后我必须覆盖 android 后退按钮，以便在dashboard按下它时退出，它可以很好地使用以下代码：
angular
.module('az-app')
.controller('DashboardController', function ($scope, $state, $ionicPlatform) {
/**
* While user on dashboard.html we don't want Android back button to return
* to tutorial views so we override it so that in case that back button is pressed
* to exit app which is in accordance with android lifecycle.
*
*/
$ionicPlatform.registerBackButtonAction(function () {
if($state.is('/dashboard') || $state.is('dashboard')){
navigator.app.exitApp();
}
}, 100);
});
现在的问题是，当我转到以下视图时，它仍然可以用作退出按钮，但我希望它只是任何其他不是仪表板的视图中的后退按钮，所以我在以下控制器中尝试了这个：
angular
.module('az-app')
.controller('DirMedicoController', function ($scope, $state, $ionicPlatform) {
$ionicPlatform.registerBackButtonAction(function () {
navigator.app.backHistory();
}, 100);
});
所以现在它返回了功能，但是当dashboard我从过去的控制器按下返回时，它会覆盖它的功能，现在而不是退出它会返回。
更新
感谢 mudasser ajaz 在下面的回答，我终于可以让它工作了，答案是：
angular
.module('az-app')
.controller('DashboardController', function ($scope, $state, $ionicPlatform, $location, $ionicHistory) {
/**
* While user on dashboard.html we don't want Android back button to return
* to tutorial views so we override it so that in case that back button is pressed
* to exit app which is in accordance with android lifecycle.
*
* Else if not on dashboard just work as normal back button
*
*/
$ionicPlatform.registerBackButtonAction(function() {
if ($location.path() === "/dashboard") {
navigator.app.exitApp();
}
else {
$ionicHistory.goBack();
}
}, 100);
$scope.backToPolicy = function () {
$state.go('intro');
}
$scope.showDirMedico = function () {
$state.go('dirmedico');
}
});