3

我有一个简单的@RestController服务,它接受查询参数,spring 自动将它们解析为bean

@ResponseStatus(HttpStatus.OK)
@RequestMapping(value = "/rest", method = RequestMethod.GET)
public MyDTO getGiataHotel(@Valid MyParams p) {
    Sysout(p.getId()); //prints "123"
}

public class MyParams {
    private int id;
    //private SubParams subs;
}

询问:.../rest?id=123

现在我想用嵌套类来构造参数对象。我怎样才能做到这一点?

public class SubParams {
   private String name;
   //some more
}

理想情况下,我的查询应该是: Query: .../rest?id=123&name=test,并且“test”字符串应该进入SubParamsbean。

那可能吗?

4

3 回答 3

1

如果需要设置为内部类,则必须注册自定义 Covertor。变化如下:

@ResponseStatus(HttpStatus.OK)
@RequestMapping(value = "/rest", method = RequestMethod.GET)
public MyDTO getGiataHotel(@ModelAttribute("subParam") MyParams params, @Valid MyParams p) {
    //Do stuff
}

subParam表示有一个为转换注册的转换器

public class MyParamsConverter implements Converter<String, MyParams> {

    @Override
    public MyParams convert(String name) {
        MyParams myParams = new MyParams();
        SubParams subParams = new SubParams();
        subParams.setName(name);
        myParams.setSubParams(subParams);
        return myParams;
    }

}
于 2015-09-01T09:04:47.563 回答
0

您可以通过使用 @ModelAttribute 注释来实现这一点:http: //docs.spring.io/spring/docs/3.1.x/spring-framework-reference/html/mvc.html#mvc-ann-modelattrib-method-args(这不在 Path 参数中,而是在 requestParams 中获取/发布)

@RequestMapping(value="/owners/{ownerId}/pets/{petId}/edit", method =   RequestMethod.POST)
public String processSubmit(@ModelAttribute("pet") Pet pet, BindingResult result) {

     if (result.hasErrors()) {
         return "petForm";
     } 

     // ...       

}
于 2015-09-01T08:47:06.423 回答
0

也许你应该使用 RequestMethod.POST,像这样

@RequestMapping(value = "/rest", method =   RequestMethod.POST)
public ModelAndView getGiataHotel(@ModelAttribute("subparams") SubParams subparams){
      SubParams sub=subparams;
      //do something...
}
于 2015-09-01T09:06:36.550 回答