javascript - 在混合的 php/javascript 函数中选择正确的 ' 和 "

Question

我正在使用甜蜜的警报插件来获得精美的 javascript 警报。但是当 $_GET 变量中有东西时，你只需要一个警报。没问题。然后我在“文本”中放入了一个 facebook 框，脚本被破坏了。我发现没有 php if 语句它可以工作，所以问题必须是行的 ' 和 "：

echo 'text: "Thank you so much for your support!<br><br><small>
Now please follow us on Facebook.</small><br><br><div class="fb-follow" 
data-href0="https://www.facebook.com/pages/Juuin/1618729241739708" 
data-layout="box_count" data-show-faces="true"></div>",';` 

整个脚本如下所示：

    <?php
if($_GET['reg'] == "sucess"){
    echo '<script>';
    echo 'sweetAlert({';
    echo 'title: "You did it!",'; 
    echo 'text: "Thank you so much for your support!<br><br><small>Now please follow us on Facebook.</small><br><br><div class="fb-follow" data-href0="https://www.facebook.com/pages/Juuin/1618729241739708" data-layout="box_count" data-show-faces="true"></div>",'; 
    echo 'html: true';
    echo '});';
    echo '</script>';
}
   ?>

Answer 1

尝试这个

<?php
if($_GET['reg'] == "sucess"){
   echo '<script> sweetAlert({title: "You did it!",text: "Thank you so much for your support!<br><br><small>Now please follow us on Facebook.</small><br><br><div class="fb-follow" data-href0="https://www.facebook.com/pages/Juuin/1618729241739708" data-layout="box_count" data-show-faces="true"></div>", html: true }); </script>';
}
   ?>

让我知道它是否有帮助