我有一个 android 应用程序,它使用 Robospice 和 Google HTTP 客户端向服务器发送 RESTful 请求。如果结果成功返回,一切正常,但如果我的服务返回异常,Robospice 侦听器不会捕获异常。
public final class FBUserSaveListener implements RequestListener<HttpResponse> {
@Override
public void onRequestFailure( SpiceException spiceException ) {
if(progressDialog.isShowing())
{
progressDialog.dismiss();
}
Toast.makeText(getActivity(),
"Error: " + spiceException.getMessage(), Toast.LENGTH_SHORT)
.show();
Intent i = new Intent(getActivity(), ErrorActivity.class);
startActivity(i);
}
@Override
public void onRequestSuccess(HttpResponse response) {
if (progressDialog.isShowing()) {
progressDialog.dismiss();
}
if(response.getStatusCode() == AppConstants.HTTP_CODE_CREATED_201) {
Intent intent = new Intent(getActivity(), PoolMainActivity.class);
startActivity(intent);
}
else{
//Request was sent successfully but the response was wrong
// Redirect to error page
Intent i = new Intent(getActivity(), ErrorActivity.class);
startActivity(i);
}
}
}
在上面的代码中,当外部服务返回异常时,onRequestFailure() 根本没有命中。
我的要求是:
public HttpResponse loadDataFromNetwork() throws Exception{
String url = context.getString(R.string.BASE_SERVICE_URL) + context.getString(R.string.USER_FB_LOGIN_SAVE);
HttpRequest request = getHttpRequestFactory()//
.buildPostRequest(new GenericUrl(url), ByteArrayContent.fromString("application/json", fbLoginBeanJson));
request.setParser(new com.google.api.client.json.jackson2.JacksonFactory().createJsonObjectParser());
return request.execute();
}
我是否错过了 RESTful 服务的 Robospice 实现中的某些内容?