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我正在使用 spark 1.3.1，我想将数据作为 ORC 格式存储在 hive 中。

下面显示错误的行，看起来 orc 不支持作为 spark 1.3.1 中的数据源

dataframe.save("/apps/hive/warehouse/person_orc_table_5", "orc");

java.lang.RuntimeException: Failed to load class for data source: orc
    at scala.sys.package$.error(package.scala:27)
    at org.apache.spark.sql.sources.ResolvedDataSource$.lookupDataSource(ddl.scala:194)
    at org.apache.spark.sql.sources.ResolvedDataSource$.apply(ddl.scala:237)
    at org.apache.spark.sql.DataFrame.save(DataFrame.scala:1196)
    at org.apache.spark.sql.DataFrame.save(DataFrame.scala:1156)
    at SparkOrcHive.main(SparkOrcHive.java:62)
    at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
    at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:57)
    at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
    at java.lang.reflect.Method.invoke(Method.java:606)
    at org.apache.spark.deploy.SparkSubmit$.org$apache$spark$deploy$SparkSubmit$$runMain(SparkSubmit.scala:577)
    at org.apache.spark.deploy.SparkSubmit$.doRunMain$1(SparkSubmit.scala:174)
    at org.apache.spark.deploy.SparkSubmit$.submit(SparkSubmit.scala:197)
    at org.apache.spark.deploy.SparkSubmit$.main(SparkSubmit.scala:112)
    at org.apache.spark.deploy.SparkSubmit.main(SparkSubmit.scala)

Spark 1.4 有..

write.format("orc").partitionBy("age").save("peoplePartitioned")

存储为兽人格式..

有没有办法在 spark 1.3.1 中以 ORC 格式存储文件？

谢谢，

4

1 回答 1

1 
(
    dataframe.select("name", "age")
    .save("/apps/hive/warehouse/orc_table", 
          "org.apache.spark.sql.hive.orc", 
          SaveMode.Append);
)

编辑 ：

我正在从 hdfs 获取 txt 文件并将数据以 orc 格式写入配置单元表。下面的代码在 spark 1.3.1 中对我来说工作正常

java类

package com.test.spark;

import org.apache.spark.SparkConf;
import org.apache.spark.api.java.JavaRDD;
import org.apache.spark.api.java.JavaSparkContext;
import org.apache.spark.api.java.function.Function;
import org.apache.spark.sql.DataFrame;
import org.apache.spark.sql.SaveMode;
import org.apache.spark.sql.hive.HiveContext;

/**
 * Created by ankit on 08/02/16.
 */
public class SparkOrcHiveInsert {

    public static void main(String[] args) {

        String tableName = "person_orc";
        String tablePath = "/apps/hive/warehouse/" + tableName;

        SparkConf conf = new SparkConf().setAppName("ORC Demo").setMaster("local");
        JavaSparkContext sc = new JavaSparkContext(conf);

        HiveContext hiveContext = new org.apache.spark.sql.hive.HiveContext(sc.sc());

        JavaRDD<Person> people = sc.textFile("hdfs://~:8020/tmp/person.txt").map(
                new Function<String, Person>() {
                    public Person call(String line) throws Exception {
                        return process(line);
                    }
                });


        DataFrame schemaPeople = hiveContext.createDataFrame(people, Person.class);
        schemaPeople.select("id","name", "age").save(tablePath, "org.apache.spark.sql.hive.orc", SaveMode.Append);
    }

    private static Person process(String line) {
        String[] parts = line.split(",");
        Person person = new Person();
        person.setId(Integer.parseInt(parts[0].trim()));
        person.setName(parts[1]);
        person.setAge(Integer.parseInt(parts[2].trim()));

        return person;
    }
}

Hive 表脚本

create table person_orc (
  id int,
  name string,
  age int
) stored as orc tblproperties ("orc.compress"="NONE");

火花提交命令

~/spark/bin/spark-submit --master local  --class com.test.spark.SparkOrcHiveInsert spark-orc-hive-1.0.jar
于 2015-08-19T09:15:46.590 回答