1

我很难理解 interval_map 和 split_interval_map，我都实现了，结果是一样的。下面是分割区间图的代码。

#include <iostream>
#include <boost/icl/split_interval_map.hpp>
#include <boost/icl/interval_map.hpp>

using namespace std;
using namespace boost::icl;


/* The most simple example of an interval_map is an overlap counter.
   If intervals are added that are associated with the value 1,
   all overlaps of added intervals are counted as a result in the
   associated values. 
*/
typedef split_interval_map<int, int> OverlapCounterT;

void print_overlaps(const OverlapCounterT& counter)
{
    for(OverlapCounterT::const_iterator it = counter.begin(); it != counter.end(); it++)
    {
        discrete_interval<int> itv  = (*it).first;
        int overlaps_count = (*it).second;
        if(overlaps_count == 1)
            cout << "in interval " << itv << " intervals do not overlap" << endl;
        else
            cout << "in interval " << itv << ": "<< overlaps_count << " intervals overlap" << endl;
    }
}

void overlap_counter()
{
    OverlapCounterT overlap_counter;
    discrete_interval<int> inter_val;

    inter_val = discrete_interval<int>::right_open(4,9);
    cout << "adding   " << inter_val << endl;
    overlap_counter += make_pair(inter_val, 1);
    print_overlaps(overlap_counter);

    inter_val = discrete_interval<int>::right_open(6,9);
    cout << "adding   " << inter_val << endl;
    overlap_counter += make_pair(inter_val, 1);
    print_overlaps(overlap_counter);


    inter_val = discrete_interval<int>::right_open(1,9);
    cout << "adding   " << inter_val << endl;
    overlap_counter += make_pair(inter_val, 1);
    print_overlaps(overlap_counter);


}

int main()
{
    cout << ">>Interval Container Library: Sample overlap_counter.cpp <<\n";
    cout << "-----------------------------------------------------------\n";
    overlap_counter();
    return 0;
}

输出是：

adding   [4,9)

in interval [4,9) intervals do not overlap

adding   [6,9)

in interval [4,6) intervals do not overlap

in interval [6,9): 2 intervals overlap

adding   [1,9)

in interval [1,4) intervals do not overlap

in interval [4,6): 2 intervals overlap

in interval [6,9): 3 intervals overlap

同样在上面的代码中，我将 split_interval_map 更改为 interval_map 并且输出相同。有什么我想念的吗？

4

1 回答 1

2

当您插入紧邻的音程时，差异会变得很明显。“正常”地图将合并它们，分裂不会（因此它保留所有间隔边界）。

另请参阅相关文档：组合样式

样本：

Live On Coliru

#include <iostream>
#include <boost/icl/split_interval_map.hpp>
#include <boost/icl/interval_map.hpp>
namespace icl = boost::icl;

template <typename Map> void test() {
    std::cout << __PRETTY_FUNCTION__ << ":\n";

    Map s { { Map::interval_type::right_open(2,10), 3 } };
    std::cout << s << "\n";

    s.add({ {10,12}, 3 });
    std::cout << s << "\n";
}

int main()
{
    test<icl::interval_map<int, int> >();
    test<icl::split_interval_map<int, int> >();
}

印刷

void test() [with Map = boost::icl::interval_map<int, int>]:
{([2,10)->3)}
{([2,12)->3)}
void test() [with Map = boost::icl::split_interval_map<int, int>]:
{([2,10)->3)}
{([2,10)->3)([10,12)->3)}
于 2015-08-18T16:01:46.623 回答