python - Flask 重定向到 url 并传递查询字符串

Question

我有一个这样定义的视图：

@views.route('/issues')
def show_view():
    action = request.args.get('action')
method = getattr(process_routes, action)
return method(request.args)

在我的 process_routes 模块中，我想调用这个方法，并传递查询字符串值。我有以下代码：

return redirect(url_for('views.show_view', action='create_or_update_success'))

我在 process_routes 中有一个名为 create_or_update_success 的函数

我正进入（状态

BuildError: ('views.show_view', {'action': 'create_or_update_success'}, None)

意见是一个蓝图。我可以成功调用

/issues?action=create_or_update_success

在我的浏览器中。

我究竟做错了什么？

Answer 1

The first part, views., has to reflect the first argument you give to your Blueprint() object exactly.

Don't be tempted to set that first argument to __name__, as that is likely to contain the full path of the module when inside a package. In your case I suspect that to be some_package.views rather than just views.

Use a string literal for the Blueprint() first argument instead:

views_blueprint = Blueprint('views', __name__)

so you can refer to url_for('views.show_view') without getting build errors.