7

I am trying to create a weather app with OpenWeatherMap API for javascript. The code for my web app is :

<!DOCTYPE html>
<html> 
    <head>
        <title>Weather</title>
        <script src = "http://ajax.aspnetcdn.com/ajax/jQuery/jquery-1.6.2.min.js"></script>
        <script>
            function gettingJSON(){
                document.write("jquery loaded");
                $.getJSON("api.openweathermap.org/data/2.5/weather?q=London&APPID=ee6596241130f193adf1ba90e625cc10",function(json){
                document.write(json);
            }
        </script>
    </head>
    <body>
        <button id = "getIt" onclick = "gettingJSON()">Get JSON</button>
    </body>
</html>

What am I getting wrong here?

4

1 回答 1

9

你还没有完成parenthesis方法getJSON。除此之外，我对您的代码做了一些修改。

<!DOCTYPE html>
<html>
<head>
<title>Weather</title>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script>
    function gettingJSON(){
        document.write("jquery loaded");
        $.getJSON("http://api.openweathermap.org/data/2.5/weather?q=London&APPID=ee6596241130f193adf1ba90e625cc10",function(json){
            document.write(JSON.stringify(json));
        });
    }
    </script>
</head>
<body>
<button id = "getIt" onclick = "gettingJSON()">Get JSON</button>
</body>
</html>

http://jsfiddle.net/kqLeh3mz/

于 2015-08-15T08:11:16.583 回答