5

语境

我们的应用程序将大量数据存储在内存中的许多不同类型的地图中,以允许快速查找。为了简单起见(不考虑原始地图),它始终是带有一个或多个键的地图。性能对我们来说是一个很大的要求。

问题

我想找到性能最高的地图实现,并按照这里的建议,比较了这些实现:

  1. 基于 java.util.HashMap 的 Maps Maps (Nested Maps) 专门用于 3 个键:

    Map<K1, Map<K2, Map<K3, V>>>
    
  2. java.util.HashMap 中的包装键(元组作为键)

    Map<Triple<K1, K2, K3>, V>
    
  3. 元组作为 net.openhft.koloboke.collect.map.hash.HashObjObjMap 中的键,根据这个应该是最快的映射(之一)。

    HashObjObjMap<Triple<K1, K2, K3>, V>
    

期望

  1. 嵌套地图将具有最快的 GET 和最慢的 PUT。
  2. Koloboke hash map 会比 jdk HashMap 快。

结果

Benchmark                                                Mode  Cnt   Score   Error  Units
TupleVsNestedMapsBenchmark.benchGetFromNestedMap         avgt   20  11.586 ± 0.205  ns/op
TupleVsNestedMapsBenchmark.benchGetFromTupleKolobokeMap  avgt   20  18.619 ± 0.113  ns/op
TupleVsNestedMapsBenchmark.benchGetFromTupleMap          avgt   20   8.985 ± 0.085  ns/op
TupleVsNestedMapsBenchmark.benchPutToNestedMap           avgt   20  15.106 ± 0.142  ns/op
TupleVsNestedMapsBenchmark.benchPutToTupleKolobokeMap    avgt   20  22.533 ± 0.335  ns/op
TupleVsNestedMapsBenchmark.benchPutToTupleMap            avgt   20   8.884 ± 0.084  ns/op

基准

@OutputTimeUnit(TimeUnit.NANOSECONDS)
@BenchmarkMode(Mode.AverageTime)
@OperationsPerInvocation(100000)
@Fork(1)
@Warmup(iterations = 10)
@Measurement(iterations = 20)
public class TupleVsNestedMapsBenchmark {

public static final int N = 10000;

static ObjObjObjObjHashMap<String, String, String, Integer> sourceNestedMap = new ObjObjObjObjHashMap<>();
static Map<Triple<String, String, String>, Integer> sourceTupleMap = new HashMap<>();
static HashObjObjMap<Triple<String, String, String>, Integer> sourceTupleKMap = HashObjObjMaps.newMutableMap();

static {
    for (int i = 0; i < N; i++) {
        sourceNestedMap.put("a-" + i, "b-" + i, "c-" + i, i);
        sourceTupleMap.put(ImmutableTriple.of("a-" + i, "b-" + i, "c-" + i), i);
        sourceTupleKMap.put(ImmutableTriple.of("a-" + i, "b-" + i, "c-" + i), i);
    }
}

@Benchmark
public List<Integer> benchGetFromNestedMap() {
    return benchmarkGet(sourceNestedMap::get);
}

@Benchmark
public List<Integer> benchGetFromTupleMap() {
    return benchmarkGet(((key1, key2, key3) -> sourceTupleMap.get(ImmutableTriple.of(key1, key2, key3))));
}

@Benchmark
public List<Integer> benchGetFromTupleKolobokeMap() {
    return benchmarkGet(((key1, key2, key3) -> sourceTupleKMap.get(ImmutableTriple.of(key1, key2, key3))));
}

@Benchmark
public ObjObjObjObjHashMap<String, String, String, Integer> benchPutToNestedMap() {
    ObjObjObjObjHashMap<String, String, String, Integer> map = new ObjObjObjObjHashMap<>();

    benchmarkPut(map::put);

    return map;
}

@Benchmark
public Map<Triple<String, String, String>, Integer> benchPutToTupleMap() {
    Map<Triple<String, String, String>, Integer> map = new HashMap<>();

    benchmarkPut((key1, key2, key3, value) -> map.put(ImmutableTriple.of(key1, key2, key3), value));

    return map;
}

@Benchmark
public Map<Triple<String, String, String>, Integer> benchPutToTupleKolobokeMap() {
    HashObjObjMap<Triple<String, String, String>, Integer> map = HashObjObjMaps.newMutableMap();

    benchmarkPut((key1, key2, key3, value) -> map.put(ImmutableTriple.of(key1, key2, key3), value));

    return map;
}

private List<Integer> benchmarkGet(MapValueSupplier<Integer> mapValueSupplier) {
    List<Integer> result = new ArrayList<>(N);
    for (int i = 0; i < N; i++) {
        result.add(mapValueSupplier.supply("a-" + i, "b-" + i, "c-" + i));

    }
    return result;
}

private void benchmarkPut(PutValueFunction<Integer> putValueFunction) {
    for (int i = 0; i < N; i++) {
        putValueFunction.apply("a-" + i, "b-" + i, "c-" + i, i);
    }
}

private interface MapValueSupplier<T> {

    T supply(String key1, String key2, String key3);
}

private interface PutValueFunction<T> {

    void apply(String key1, String key2, String key3, T value);
}
}

注意:请不要建议使用原始地图。Integer as (value) 只是廉价对象的一个​​例子。

问题

  1. 为什么koloboke地图比jdk地图慢2.5倍?
  2. 为什么嵌套地图不更快?(我希望元组键对象的分配开销会更大。)
  3. 还是我的基准错误?那么,我该如何改进呢?

更新

根据@leventov 的好建议,我更改了基准测试并尝试了缓存哈希码(并且具有更好的分布)的 Triple 实现 - 测试被命名为 Tuple2。

@State(Scope.Thread)
@OutputTimeUnit(TimeUnit.NANOSECONDS)
@BenchmarkMode(Mode.AverageTime)
@OperationsPerInvocation(TupleVsNestedMapsBenchmark.TOTAL_OPS)
@Fork(1)
@Warmup(iterations = 5)
@Measurement(iterations = 20)
public class TupleVsNestedMapsBenchmark {

static final int N = 30;
static final int TOTAL_OPS = N * N * N;

private ObjObjObjObjHashMap<String, String, String, Integer> sourceNestedMap;
private Map<Triple<String, String, String>, Integer> sourceTupleMap;
private HashObjObjMap<Triple<String, String, String>, Integer> sourceTupleKMap;
private Map<Triple<String, String, String>, Integer> sourceTuple2Map;
private HashObjObjMap<Triple<String, String, String>, Integer> sourceTuple2KMap;
private String[] keys;

@Setup
public void init() {
    sourceNestedMap = new ObjObjObjObjHashMap<>();
    sourceTupleMap = new HashMap<>(TOTAL_OPS);
    sourceTupleKMap = HashObjObjMaps.newMutableMap(TOTAL_OPS);
    sourceTuple2Map = new HashMap<>(TOTAL_OPS);
    sourceTuple2KMap = HashObjObjMaps.newMutableMap(TOTAL_OPS);
    keys = new String[N];
    for (int i = 0; i < N; i++) {
        keys[i] = "k" + i;
    }
    for (int i = 0; i < N; i++) {
        for (int j = 0; j < N; j++) {
            for (int k = 0; k < N; k++) {
                sourceNestedMap.put(keys[i], keys[j], keys[k], i);
                sourceTupleMap.put(ImmutableTriple.of(keys[i], keys[j], keys[k]), i); 
                sourceTupleKMap.put(ImmutableTriple.of(keys[i], keys[j], keys[k]), i); 
                sourceTuple2Map.put(ImmutableTriple2.of(keys[i], keys[j], keys[k]), i);
                sourceTuple2KMap.put(ImmutableTriple2.of(keys[i], keys[j], keys[k]), i);
            }
        }
    }
}

@Benchmark
public List<Integer> benchGetFromNestedMap() {
    return benchmarkGet(sourceNestedMap::get);
}

@Benchmark
public List<Integer> benchGetFromTupleMap() {
    return benchmarkGet(((key1, key2, key3) -> sourceTupleMap.get(ImmutableTriple.of(key1, key2, key3))));
}

@Benchmark
public List<Integer> benchGetFromTupleKolobokeMap() {
    return benchmarkGet(((key1, key2, key3) -> sourceTupleKMap.get(ImmutableTriple.of(key1, key2, key3))));
}

@Benchmark
public List<Integer> benchGetFromTuple2Map() {
    return benchmarkGet(((key1, key2, key3) -> sourceTuple2Map.get(ImmutableTriple2.of(key1, key2, key3))));
}

@Benchmark
public List<Integer> benchGetFromTuple2KolobokeMap() {
    return benchmarkGet(((key1, key2, key3) -> sourceTuple2KMap.get(ImmutableTriple2.of(key1, key2, key3))));
}

@Benchmark
public ObjObjObjObjHashMap<String, String, String, Integer> benchPutToNestedMap() {
    ObjObjObjObjHashMap<String, String, String, Integer> map = new ObjObjObjObjHashMap<>();
    benchmarkPut(map::put);
    return map;
}

@Benchmark
public Map<Triple<String, String, String>, Integer> benchPutToTupleMap() {
    Map<Triple<String, String, String>, Integer> map = new HashMap<>();
    benchmarkPut((key1, key2, key3, value) -> map.put(ImmutableTriple.of(key1, key2, key3), value));
    return map;
}

@Benchmark
public Map<Triple<String, String, String>, Integer> benchPutToTupleKolobokeMap() {
    HashObjObjMap<Triple<String, String, String>, Integer> map = HashObjObjMaps.newMutableMap();
    benchmarkPut((key1, key2, key3, value) -> map.put(ImmutableTriple.of(key1, key2, key3), value));
    return map;
}

@Benchmark
public Map<Triple<String, String, String>, Integer> benchPutToTuple2Map() {
    Map<Triple<String, String, String>, Integer> map = new HashMap<>();
    benchmarkPut((key1, key2, key3, value) -> map.put(ImmutableTriple2.of(key1, key2, key3), value));
    return map;
}

@Benchmark
public Map<Triple<String, String, String>, Integer> benchPutToTuple2KolobokeMap() {
    HashObjObjMap<Triple<String, String, String>, Integer> map = HashObjObjMaps.newMutableMap();
    benchmarkPut((key1, key2, key3, value) -> map.put(ImmutableTriple2.of(key1, key2, key3), value));
    return map;
}

private List<Integer> benchmarkGet(MapValueSupplier<Integer> mapValueSupplier) {
    List<Integer> result = new ArrayList<>(TOTAL_OPS);
    for (int i = 0; i < N; i++) {
        for (int j = 0; j < N; j++) {
            for (int k = 0; k < N; k++) {
                Integer value = mapValueSupplier.supply(keys[i], keys[j], keys[k]);
                result.add(value);
            }
        }
    }
    return result;
}

private void benchmarkPut(PutValueFunction<Integer> putValueFunction) {
    Integer value = 1;
    for (int i = 0; i < N; i++) {
        for (int j = 0; j < N; j++) {
            for (int k = 0; k < N; k++) {
                putValueFunction.apply(keys[i], keys[j], keys[k], value);
            }
        }
    }
}

private interface MapValueSupplier<T> {

    T supply(String key1, String key2, String key3);
}

private interface PutValueFunction<T> {

    void apply(String key1, String key2, String key3, T value);
}
}

结果是这样的:

Benchmark                                                 Mode  Cnt      Score      Error  Units
TupleVsNestedMapsBenchmark.benchGetFromNestedMap          avgt   20     24.524 ±    0.144  ns/op
TupleVsNestedMapsBenchmark.benchGetFromTuple2KolobokeMap  avgt   20     65.604 ±    1.135  ns/op
TupleVsNestedMapsBenchmark.benchGetFromTuple2Map          avgt   20     22.653 ±    0.745  ns/op
TupleVsNestedMapsBenchmark.benchGetFromTupleKolobokeMap   avgt   20  34824.901 ± 1718.183  ns/op
TupleVsNestedMapsBenchmark.benchGetFromTupleMap           avgt   20   2565.835 ±   57.402  ns/op
TupleVsNestedMapsBenchmark.benchPutToNestedMap            avgt   20     43.160 ±    0.340  ns/op
TupleVsNestedMapsBenchmark.benchPutToTuple2KolobokeMap    avgt   20    237.300 ±    3.362  ns/op
TupleVsNestedMapsBenchmark.benchPutToTuple2Map            avgt   20     40.952 ±    0.535  ns/op
TupleVsNestedMapsBenchmark.benchPutToTupleKolobokeMap     avgt   20  52315.769 ±  399.769  ns/op
TupleVsNestedMapsBenchmark.benchPutToTupleMap             avgt   20   3205.538 ±   44.306  ns/op

概括

  • 如果键类的哈希码函数没有被缓存和/或分布良好,“元组”方法可能会变得非常慢,尤其是对于 koloboke。
  • 正如这里所得出的结论(在这个(Obj-Obj)案例中),java.util.HashMap 是“非常”快的。
4

3 回答 3

8

[回答更新的问题。]

好吧,基准仍然存在问题:

  • 在创建State生命周期时,您应该将状态对象作为参数传递给 benhcmark 方法(请参阅下面的代码)。
  • Benchmarking put()s 应该以不同的方式进行:1)在 @Setup 方法中,应该创建集合(带有足够的capacitysize参数)2)在另一个@Setup(Level.Invocation)方法中,你应该调用3)在 benchmark 方法中collection.clear()测量 pure sput()

  • 你仍然在基准测试方法中做了很多分配。这可能是您的情况,但它隐藏了收集性能贡献。

所以,我写的是:

package tests;

import net.openhft.koloboke.collect.map.hash.HashObjObjMap;
import net.openhft.koloboke.collect.map.hash.HashObjObjMaps;
import org.apache.commons.lang3.tuple.Triple;
import org.openjdk.jmh.annotations.*;

import java.util.HashMap;
import java.util.Map;
import java.util.concurrent.TimeUnit;

@OutputTimeUnit(TimeUnit.NANOSECONDS)
@BenchmarkMode(Mode.AverageTime)
@Fork(1)
@Threads(1)
@Warmup(iterations = 10)
@Measurement(iterations = 20)
@State(Scope.Thread)
public class SoMultiMap {

    public static final int N = Integer.getInteger("runs", 100000);

    private static final double kbk = Double.parseDouble(System.getProperty("kbk", "1.0"));

    static class ImmutableTriple<L, M, R> extends Triple<L, M, R> {
        public final L left;
        public final M middle;
        public final R right;
        private int h;

        public static <L, M, R> ImmutableTriple<L, M, R> of(L left, M middle, R right) {
            return new ImmutableTriple(left, middle, right);
        }

        public ImmutableTriple(L left, M middle, R right) {
            this.left = left;
            this.middle = middle;
            this.right = right;
        }

        public L getLeft() {
            return this.left;
        }

        public M getMiddle() {
            return this.middle;
        }

        public R getRight() {
            return this.right;
        }

        private int innerHash() {
            int h = left.hashCode();
            h *= 1000003;
            h += middle.hashCode();
            h *= 1000003;
            h += right.hashCode();
            return h * 1000003;
        }

        @Override
        public int hashCode() {
            return h != 0 ? h : (h = innerHash());
        }

        @Override
        public boolean equals(Object obj) {
            if (!(obj instanceof ImmutableTriple))
                return super.equals(obj);
            ImmutableTriple triple = (ImmutableTriple) obj;
            if (h != 0 && triple.h != 0 && h != triple.h)
                return false;
            return super.equals(obj);
        }
    }

    ImmutableTriple<String, String, String>[] keys = new ImmutableTriple[N];
    Integer[] values = new Integer[N];
    Map<Triple<String, String, String>, Integer> sourceTupleMap;
    HashObjObjMap<Triple<String, String, String>, Integer> sourceTupleKMap;

    @Setup
    public void fill() {
        sourceTupleMap = new HashMap<>((int) (N / 0.75));
        sourceTupleKMap = HashObjObjMaps.newUpdatableMap((int) (N * kbk));
        for (int i = 0; i < N; i++) {
            keys[i] = ImmutableTriple.of("a-" + i, "b-" + i, "c-" + i);
            values[i] = i;
            sourceTupleKMap.put(keys[i], values[i]);
            sourceTupleMap.put(keys[i], values[i]);
        }
    }

    @Benchmark
    public int tupleHashMapGet(SoMultiMap st) {
        ImmutableTriple<String, String, String>[] keys = st.keys;
        Map<Triple<String, String, String>, Integer> map = st.sourceTupleMap;
        int s = 0;
        for (int i = 0; i < N; i++) {
            s += map.get(keys[i]);
        }
        return s;
    }

    @Benchmark
    public int tupleKolobokeGet(SoMultiMap st) {
        ImmutableTriple<String, String, String>[] keys = st.keys;
        HashObjObjMap<Triple<String, String, String>, Integer> map = st.sourceTupleKMap;
        int s = 0;
        for (int i = 0; i < N; i++) {
            s += map.get(keys[i]);
        }
        return s;
    }

    public static void main(String[] args) {
        SoMultiMap st = new SoMultiMap();
        st.fill();
        st.tupleKolobokeGet(st);
        st.tupleHashMapGet(st);
    }
}

现在有趣的是结果:

使用 Java 7u55:

HashMap:  65 +- 6 ns/op
Koloboke: 46 +- 2

使用 Java 8u51:

HashMap:  42 +- 0.5
Koloboke: 49 +- 1

因此,我们进行了一些虚拟机更改,介于两者之间,这HashMap大大加快了速度,而Koloboke地图 - 稍微慢了一点。这需要调查,我现在没有时间。见https://github.com/OpenHFT/Koloboke/issues/42

另外,请注意几件事:

  • 在服务器 VM 上运行基准测试
  • 在运行期间禁用 CPU 缩放
  • 关闭繁重的应用程序(浏览器、Intellij 等),除非您有 16 个以上的硬件线程
于 2015-08-13T17:26:58.323 回答
1

您的基准问题列表:

  • 初始化在静态区域完成,应该用@Setup方法和@States来完成
  • 基准内大量分配,并构建字符串!你实际测量的是什么?
  • 注意一个错误 -N是 10K,但是operationsPerInvocation是 100K,所以实际时间非常令人沮丧
  • 糟糕的String哈希码 + 非常糟糕的Triple哈希码,导致哈希表中出现一些聚集
  • 在测试嵌套与元组时,请注意您已将所有键的所有部分都选择为唯一的,即所有嵌套映射都是具有单个键的映射。这可能不是你想要的
于 2015-08-11T19:11:42.110 回答
0

Triple 作为抽象是可以的(至少,我没有看到明显更好的选择,您可以覆盖 Apache Commons 的Triple抽象类来定义更好的hashCode()功能。

final class ImmutableTriple<L, M, R> extends Triple<L, M, R> {
    public final L left;
    public final M middle;
    public final R right;
    private int h;

    public static <L, M, R> ImmutableTriple<L, M, R> of(L left, M middle, R right) {
        return new ImmutableTriple(left, middle, right);
    }

    public ImmutableTriple(L left, M middle, R right) {
        this.left = left;
        this.middle = middle;
        this.right = right;
    }

    public L getLeft() {
        return this.left;
    }

    public M getMiddle() {
        return this.middle;
    }

    public R getRight() {
        return this.right;
    }

    private int innerHash() {
        int h = left.hashCode();
        h *= 1000003;
        h += middle.hashCode();
        h *= 1000003;
        h += right.hashCode();
        return (int) LongHashFunction.murmur_3().hashInt(h);
    }

    @Override
    public int hashCode() {
        return h != 0 ? h : (h = innerHash());
    }
}
于 2015-08-12T14:57:12.660 回答